Newtonian theory of universal attraction
585
22
12
11
XY
ξ
ξξ
≤+<
+
,
22
2
(2 )
1
YX
ξ
ξξ
ξ
+−≥
,
(9.2.47)
to which we associate the condition (9.2.42'); we took into account the notation
(9.2.41). The first inequalities show that the point
(,)XYP must be in the interior of
the circular annulus, bounded by the circles
1
C and
2
C of radii
1
(1 )/(1 )ρξξ=− + and
2
2/(1 )ρξ=+, respectively, or on the internal frontier
of it (Fig.9.15). As well, this point must be interior to the hyperbola
H of equation
(regions of the plane which do not contain the origin
O
)
22
22
1
YX
βα
=
(9.2.48)
and of semiaxes
2/(1 )αξξ=+ and 2/(1 )(2 )βξξ=++; the foci (0, )γ and
(0, )γ− are specified by 2(1 )/(2 )γξξ=+ +. The asymptotes of the hyperbola
make an angle
ϕ given by cot (2 )ϕξξ=+ with the
OX
-axis.
If we draw a tangent from the launching point
0
P
to the Earth sphere, then we notice
that the angle
ϕ is just the angle made by this tangent with the straight line
0
PF
′
(Fig.9.13). The condition (9.2.42') leads to
0
cot (2 )αξ ξ
+ , so that
0
cot cotαϕ≤
;
hence,
0
αϕ≥
(the point (,)XYP must be in the interior of the asymptotes’ angle,
which contains the hyperbola
H, condition which is fulfilled together with the second
condition (9.2.47)). If
0
αϕ
(the point (,)XYP being in the interior of the
asymptotes’ angle, which does not contain the hyperbola
H ), then the trajectory of the
vehicle launched from the Earth surface pierces the Earth sphere immaterial of the
launching velocity. These conditions are easily justified in Fig.9.15.
We have
12
ρβρ<<. Hence, one can launch satellites of the Earth from a given
height
H , that is for a given ξ , if the initial velocity
0
v and the direction of the
launching
0
α are so that the point (,)XYP be in the interior of the domain D
bounded by arcs of hyperbola
H and arcs of circle
2
C (the hatched regions in Fig.
9.15). The points
,,
+−
PPP and
P of intersection of the hyperbola H with the
circle
2
C have the co-ordinates
2/(1 )X ξξ
±+
,
2/(1 )Y ξ
±+
. The angle
α
formed by the OY -axis with the semi-lines O
P and O
−
P is given by
arctanαξ= ; it results that the launching angle
0
α depends on ξ , hence on the
launching height
H , and that we must have
0
/2 , /2απ απ α
−+.
The point
(
0,1/ 1 ξ+ corresponds to a circular trajectory.
The discussion has been made for
0Y > ; for 0Y
one obtains analogous results
and a trajectory symmetric to the first one.
In conclusion, if the point
(,)XYP belongs to the interior of the circle
2
C , then
the trajectory is an ellipse (if
PD, then the trajectory does not intersect the Earth’s