Multiple
Pump
Operation
In
pumping stations where several pumps
are
installed,
two or
more pumps
are
usually operated
in
parallel. Occasionally, pumps
are
operated
in
series.
The
elements
of the
methods used
to
develop
the
combined
H-Q
curve
for
multiple pumps
are
outlined
in the
following subsections.
A
more
extensive explanation
for
multiple pumps
is
given
in
Section 10-8.
Parallel
Operation
When
two or
more pumps
are
discharging into
the
same header
or
manifold,
the
total
flow is
found
by
adding
the
individual
flows at a
given head.
A
correc-
tion (usually small) must
be
made, however, because
the
higher
flow
causes higher headlosses that slightly
reduce
the flow
either pump would discharge
if
oper-
ated alone.
One
method
for
combining
the flows is to
subtract
from
the
pump curve those station headlosses
in
the
suction
and
discharge piping
up to the
intersec-
affinity
laws
are
used,
as
shown
in
Example 10-8,
to
determine
the
rotational speed
at any
other desired
operating point
on the
system curve. Again,
the
oper-
ating point moves along
the
pump
H-Q
curve,
although
not so
far, because
the
change between
HWL
and
LWL is
less than with single-speed operation.
Example
10-8
Application
of a
Variable-Speed Pump
Problem:
The
pump curve shown
in
Figure 10-23
is for a
pump operated
at
1150
rev/min
that
pumps
130
m
3
/h
(572
gal/min)
at a
head
of
13.2
m
(43.3 ft), which
is
shown
as
point
a. If the
pump
must discharge
150
m
3
/h
(660 gal/min)
at a
head
of
15.5
m
(50.8 ft), which
is
shown
as
point
b,
what
is (1) the
required
new
operating speed
and (2) the
efficiency
of the new
operating
point?
Solution:
(1)
Operating
speed. Extend
the
system
H-Q
curve
from
point
a to an
intersection
with
the
desired
flowrate at
point
b. The new
pump curve must pass through point
b.
Note that
Equation 10-15
(QJQ
2
=
K
1
In
2
)
cannot
be
used
to find the
pump speed because points
a and b
are not
corresponding points (see Example 10-2
and the
text following Equation
10-17).
One
way
to
solve
the
problem
is to
create
an
"affinity
law
parabola"
by
solving Equations
10-15
and
10-16
simultaneously
to
eliminate
m
/QA
2
fn
}
\
2
H
}
2
(W
=
(^
-^
"'
=
//2(Gi/22)
which
defines
a
parabola passing through
the
origin
and
point
b in
Figure 10-23. Every point
on
the
parabola
is a
corresponding point. Because point
b
corresponds
to
point
c,
Equation 10-15
can
be
used
to find
speed
at
point
b
after
Q is
scaled
at
point
c.
Sl
Units
U.S. Customary
Units
Q
c
=
136
m
3
/h
(by
scaling)
Q
c
= 598
gal/min
(by
scaling)
From Equation
10-15
(/i
b
=
n
c
CyQ
0
),
n
b
=
1150(150/136)
=
1270
rev/min
n
b
=
1150(660/598)
=
1270
rev/min
By
scaling
H at
points
b and c, the
speed
can
also
be
found
from
Equation
10-16
(n
b
=
njH
b
/H
c
).
n
b
=
1150V15.4/12.6
=
1270
rev/min
n
b
=
1150^50.5/41.3
= 270
rev/min
(2)
Efficiency.
The
efficiency
of the new
operating point
is
found
by
projecting
a
line
from
point
c
downward
to
point
d on the
efficiency
curve, which gives
an
expected
efficiency
of
75%.