302 B Spinorial Objects
belt connecting the scissors and the chair (see Figure B.3.2). Rotate the scis-
sors through 2π and the belt acquires one twist which cannot be untwisted
by moving the belt alone. Rotate through 4π and the belt has two twists that
can be removed by looping the belt once around the scissors.
Regarding the scissors as a rigid, solid body in 3-space we now introduce
what the physicists would call its “configuration space”. Fix some position of
the scissors in space as its “original” configuration. Any continuous motion of
the scissors in space will terminate with the scissors in some new configuration
which can be completely described by giving a point in R
3
(e.g., the location
of the scissors’ center of mass) and a rotation that would carry the original
orientation of the scissors onto its new orientation. This second element of
the description we specify by giving an element of the rotation group SO(3),
i.e., the set of all 3 × 3 unimodular orthogonal matrices (when viewed as a
subgroup of the Lorentz group we denoted SO(3) by R; see Section 1.3).
Thus, the configuration space of our scissors is taken to be R
3
× SO(3).
In configuration space R
3
× SO(3) a continuous motion of the scissors in
space is represented by a continuous curve. In particular, if the initial and fi-
nal configurations are the same, by a loop. Consider, for example, some point
x
0
in R
3
×SO(3), i.e., some initial configuration of the scissors. A continuous
rotation of the scissors through 2π about some axis is represented by a loop
at x
0
in R
3
×SO(3). Dirac’s ingenious demonstration permits us to actually
“see” this loop. Indeed, let us visualize Dirac’s apparatus with the belt having
one “twist”. Now imagine the scissors free to slide along the belt toward the
chair. As it does so it completes a rotation through 2π. When it reaches the
chair, translate it (without rotation) back to its original location and one has
traversed a loop in configuration space. Similarly, for a rotation through 4π.
Indeed, it should now be clear that any position of the belt can be viewed as
representing a loop in R
3
×SO(3) (slide the scissors along the belt then trans-
late it back). Now imagine yourself manipulating the belt (without moving
scissors or chair) in an attempt to untwist it. At each instant the position of
the belt represents a loop in R
3
×SO(3) so the process itself may be thought
of as a continuous sequence of loops (parametrized, say, by time t). If you
succeed with such a sequence of loops to untwist the belt you have “created”
a homotopy from the loop corresponding to the belt’s initial configuration to
the trivial loop (no rotation, i.e., no twists, at all). What Dirac seems to be
telling us then is that the loop in R
3
×SO(3) corresponding to a 2π rotation
is not homotopically trivial, but that corresponding to a rotation through 4π
is homotopic to the trivial loop.
It is clearly of some interest then to understand the “loop structure”, i.e.,
the fundamental group, of R
3
×SO(3). Notice that SO(3) does indeed have a
natural topology. The entries in a 3×3 matrix can be strung out into a column
matrix which can be viewed as a point in R
9
.Thus,SO(3) can be viewed as a
subset of R
9
and therefore inherits a topology as a subspace of R
9
.Aconsid-
erably more informative “picture” of SO(3) can be obtained as follows: Every
rotation of R
3
can be uniquely specified by an axis of rotation, an angle and a