SYNCHRONOUS MACHINES
5-41
[]
EZTTZTYTVTe
11
1
11 −−
−
−−
+==
MMN
(5.188)
The machine terminal currents are obtained from (5.185)
]
eEZi −=
−1
M
(5.189)
Electrical power output is obtained from (5.140).
The computational steps shown in (5.188) and (5.189) are equivalent to those described in
Chapter 4 (see equations (4.27), (4.28)), where the machine internal voltage in series with the
internal impedance is first converted to a current source and machine terminal voltage is obtained
directly by multiplying the vector composed of these currents by the inverse of the modified
network admittance matrix. In (5.188), the operation EZ
1−
M
is equivalent to converting the
voltage source into current source in machine reference frame. This is then transformed to
network reference frame, followed by multiplication by the inverse of the modified network
admittance matrix to obtain the machine terminal voltage. Finally, this is transformed back to the
machine reference frame. The machine current is then obtained from (5.189).
Note that in using machine model 1, since
qd
xx
, they can be assumed equal and then
111 −−−
=
MM
ZTZT . Thus
TZTY
11 −−
+
MN
has to be inverted only once for each network
configuration. Also, with
qd
xx
′′
=
′′
, it is possible to work with equations in complex form thereby
reducing the computational burden considerably. Equation (5.188) would then be written as
]
EZTZYTe
ˆ
ˆ
11
1
1 −−
−
−
+=
MMN
(5.190)
where Ee
ˆ
and
ˆ
are the vectors of complex machine terminal and internal voltages, respectively.
N
Y is the complex network admittance matrix.
M
Z is a diagonal matrix of the complex machine
internal impedances
dii
xjr
′′
, and T is given by
=
−
−
O
)
2
π
(
)
2
π
(
2
1
δ
δ
ε
ε
j
j
T
Equation (5.189) would then become
eEZi
ˆ
ˆ
ˆ
1
−=
−
M
(5.191)
Note that in this formulation the non-generator buses can be retained. As has been pointed out in
Chapter 7, non-dynamic (or static) loads should be represented by constant impedance. Dynamic
loads (motor and non-motor) can be adequately represented by one of the induction machine
models discussed in Chapter 7. For the buses with impedance loads, the injected currents would
be zero, the block diagonal elements of
Z
M
would be 2 × 2 null matrix, the impedance having
been included in the network admittance matrix, and the corresponding elements of the
T matrix
would be 2
× 2 unit matrix. The network solution can then proceed as discussed in Chapter 4,
taking advantage of the sparsity of
Y
N
. Induction motor and other dynamic loads can be handled
following the procedure discussed in Chapter 8.