370 13 Incompressible Fluid Flows
This relationship expresses the fact that the motion of the flow between
the plates is caused by an imposed external pressure gradient. Pressure and
viscosity forces for these kinds of flows are in equilibrium for a fluid element.
As the pressure distribution dΠ/dx
1
can only be a function of x
1
(see
Sect. 13.2) and the right-hand side of the above equation depends only on x
2
,
i.e. U
1
(x
2
), dΠ/ dx
1
has to be constant for the flow between parallel plates.
Thus, we have a simple linear differential equation of second order which has
to be solved to obtain the velocity profile of the plane channel flow.
By a first integration one obtains:
dU
1
dx
2
=
1
µ
dΠ
dx
1
x
2
+ C
1
. (13.43)
This differential equation has as a general solution obtained by a second
integration:
U
1
=
1
2µ
dΠ
dx
1
x
2
2
+ C
1
x
2
+ C
2
. (13.44)
Due to the following boundary conditions:
x
2
=+D −→ U
1
=0=
1
2µ
dΠ
dx
1
D
2
+ C
1
D + C
2
, (13.45)
x
2
= −D −→ U
1
=0=
1
2µ
dΠ
dx
1
D
2
− C
1
D + C
2
(13.46)
one obtains the values for the integration constants:
C
1
=0 and C
2
= −
1
2µ
dΠ
dx
1
D
2
(13.47)
and thus the solution for the velocity distribution between the plates can be
given as follows:
U
1
= −
1
2µ
dΠ
dx
1
D
2
1 −
x
2
D
2
for − D ≤ x ≤ D. (13.48)
This relationship for the flow velocity U
1
shows that the velocity profile be-
tween the plates represents a parabola. The maximum velocity is at the center
of the channel. At the surfaces of both the plates the flow velocity is zero and
in the entire flow field U
1
is positive, because for the flow region |x
2
|≤D
holds and, hence, [1 − (x
2
/D)
2
] is always positive. However, the pressure
gradient in the x
1
direction decreases, i.e. the resultant pressure gradient is
negative, so that the velocity U
1
in the x
1
direction, according to (13.43), is
positive. Assuming that the plates in the x
3
direction have a width B,the
volumetric flow rate per unit time can be computed for the flow in Fig. 13.3
as follows: