100 4 Basics of Fluid Kinematics
the stream function requires a limitation of the considerations to those veloc-
ity fields which have to fulfill physical conditions. Considerations in Chap. 5
show that physically existing flow fields have to fulfill the mass-conservation
law, which can be formulated for ideal fluids (ρ = constant) as follows:
∂U
i
∂x
i
=
∂U
1
∂x
1
+
∂U
2
∂x
2
+
∂U
3
∂x
3
= 0 (4.71)
The stream function fulfills the mass-conservation law for two-dimensional
flows automatically and can easily be checked by inserting the definition of
ψ = in equation (4.66) and applying the Schwarz rule of differentiation.
When a prescribed velocity field does not fulfill the mass-conservation
law, the integrations to be carried out according to (4.67) and (4.68) result
in solutions that contradict one another. This can be shown for the two-
dimensional flow field shown in Sect. 4.3.1 which does not fulfill the mass-
conservation law (i.e. the continuity equation):
U
1
= x
1
,U
2
= x
2
(1 + 2t),U
3
= 0 (4.72)
When one carries out the integration stated in (4.67), one obtains from the
defining equations for the stream function, i.e. from (4.66) it results that:
∂ψ
∂x
2
= x
1
and
∂ψ
∂x
1
= −x
2
(1 + 2t) (4.73)
By integration of these equations, one obtains for the stream function:
ψ = x
1
x
2
+ F (x
1
,t),ψ= −x
1
x
2
(1 + 2t)+G(x
2
,t) (4.74)
or, expressed otherwise,
x
1
x
2
+ F (x
1
,t) = −x
1
x
2
(1 + 2t)+G(x
2
,t) (4.75a)
or
2(t +1)x
1
x
2
= G(x
2
,t) − F (x
1
,t) (4.75b)
A comparison of the results of both the integrations in equation (4.73), yields
equation (4.74), which shows the contradiction resulting for the stream func-
tion ψ. The time dependence for the x
1
x
2
part in the right-hand side of
equation (4.75a) is missing on the left-hand side. This results from the fact
that the velocity field given in (4.72), although mathematically clearly de-
fined, cannot exist physically; the velocity field in (4.72) does not fulfill the
requirements determined by the mass-conservation law for ρ = constant.
When one considers, on the other hand, the velocity field:
U
1
=exp[x
1
(1 + t)],U
2
= −x
2
(1 + t)exp[x
1
(1 + t)],U
3
= 0 (4.76)