==KKI
O
O
O
ω,
(14.1.24')
which corresponds to the relations (11.2.17), (11.2.17') where we make
=K0
O
; K
O
represents the moment of momentum with respect to the pole O in the non-inertial
frame and – in case of the rigid solid – is reduced to the pseudomoment of momentum
considered above. We state thus
Theorem 14.1.5 The moment of momentum of a rigid solid with respect to a pole
′
O
of a given inertial frame of reference
′
R
, in this frame, is equal to the sum of the
pseudomoment of momentum of the rigid solid with respect to an arbitrary pole O,
rigidly linked to the rigid solid (the contracted product of the moment of inertia tensor
with respect to the same pole by the rotation angular velocity vector of a non-inertial
frame
R with the pole at O, rigidly linked to the rigid solid, with respect to the inertial
frame), the moment of momentum of the centre of mass, translated at the pole O, where
the whole mass of the rigid solid is considered to be concentrated, taken with respect to
the pole
′
O
, in the frame
′
R
, and the moment of momentum of the pole O, translated
at the centre of mass, where it is assumed that the whole mass of the rigid solid is
concentrated, calculated with respect to the pole O, in the inertial frame
′
R
too.
In the particular case in which the frame of reference
R is of Koenig type ( = 0ω ,
hence
=K0
O
), there results the formula
() ()
′
′′ ′ ′
=× +×
Kr v v
OC O
O
MMρ .
(14.1.25)
Taking into account that this frame is rigidly linked to the rigid solid, it results that the
latter one will have a motion of translation (we are in a particular case of motion).
If the pole of the non-inertial frame coincides with the centre of mass of the rigid
solid (
≡OC, = 0ρ ), then we obtain a formula of Koenig type (in which, instead of
the moment of momentum with respect to the centre of mass, in the frame
R, which is
equal to zero, appears the corresponding pseudomoment of momentum)
()
′
′′′
=+×
KI v
CC
O
Mωρ ,
(14.1.25')
where
I
C
is the central moment of inertia tensor; thus, the motion is not particularized
and has – further – a general character. If we have also
= 0ω , then the non-inertial
frame
R is a Koenig frame and we get
()
′
′′ ′
=×
Kv
C
O
Mρ .
(14.1.25'')
Hence, the moment of momentum of a rigid solid in motion of translation, with respect
to a given frame of reference, is equal to the moment of momentum of its centre of mass
with respect to this frame, assuming that its whole mass is concentrated at this centre.
()
′
′′′ ′
=−×
KKr v
OOC
O
M ,
we obtain
()
′′
=+×
KI v
OO O
Mωρ ,
(14.1.26)
As in Sect. 11.2.2.1, starting from (14.1.23') and noting that
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MECHANICAL SYSTEMS, CLASSICAL MODELS