3.2 Elastic Properties of Dislocations 51
repel each other, depending on their respective signs. For the present question
of the glide motion of S2 on the xz plane, only the glide force f
dx
is considered,
no cross slip on other planes. The glide force is positive for positive x values
and Burgers vectors of equal sign, but negative for negative x values. This
means that screw dislocations of equal sign repel each other. For Burgers
vectors of opposite sign, the dislocations attract each other on both sides and
the equilibrium at x = 0 is stable with respect to glide on the xz plane. The
site of the maximum interaction force is found by setting
∂f
dx
∂x
=
∂σ
23
b
∂x
=
μb
2
2π
y
2
0
− x
2
(x
2
+ y
2
0
)
2
.
=0.
The solution is x
m
= ±y
0
. Putting this into (3.25) yields the maximum force
f
dxm
= ±
μb
2
4πy
0
. (3.26)
If a moving dislocation is to bypass another one, the maximum interac-
tion force has to be overcome by applying an external stress, in this case σ
23
.
Both the maximum interaction force and the necessary stress to overcome this
force are proportional to 1/y
0
, i.e., the reciprocal distance between the slip
plane of the gliding dislocation and the dislocation causing the internal stress
field. During plastic deformation, the dislocation density increases and, conse-
quently, y
0
decreases. Thus, to continue plastic deformation, the applied stress
has to increase. This is an essential source of hardening during deformation,
the so-called work-hardening.
For plastic deformation, the behavior of edge dislocations is important,
too. The stress field of edge dislocations was introduced in (3.11) and Fig. 3.9.
For the bypassing of two parallel edge dislocations extending in z direction
with Burgers vectors parallel to x and a distance y
0
between their slip planes,
the stress component σ
12
in Fig. 3.9c is relevant. Again, one dislocation moves
as a probe in the stress field of the other one located at the origin. There are
positions of zero stress for x =0andx = ±y
0
. For parallel Burgers vectors, the
signs in Fig. 3.9c indicate the directions of the force. For example, near x =0
and x>0 the probe dislocation is pushed to the left, and for x<0tothe
right, i.e., the equilibrium is stable. Table 3.1 presents the stability conditions
of all equilibrium positions for equal and opposite signs of the Burgers vectors.
It shows the stable position for equal signs at x = 0, corresponding to the tilt
grain boundary, and for opposite signs at x = ±y
0
, corresponding to the edge
dipole. Thus, the edge dislocation dipoles are stable in a position of 45
◦
with
respect to the direction of the Burgers vector.
The maximum force between two bypassing edge dislocations can be
determined in the same way as described earlier for screw dislocations, yielding
f
dm
=
μb
2
8π(1 − ν)y
0
.