IV,§1,2
245
The search for solutions y of (2.16) satisfying (2.18) is a classical problem:
(f - 4Hm)r3 + Log(Q1 sin 0 + o3 cos O)
is a self-adjoint matrix with zero trace; it is a periodic function of t; the
period is c[L0, Mo]; then the 2 x 2 matrix u(t) defined by
du + i[(f - IHM)Q3 + Log(Q1 sin 0 + o3 cos O)]u dt = 0,
u(0) = 1,
(2.20)
is a unitary matrix with determinant 1, that is, u c- SU(2); it satisfies
u(t + c[L0, Mo]) = u(t)u(c[L0, MO]);
the general solution of (2.16) is
y(t) = u(t)d, where 6 E C2;
y satisfies (2.18) if and only if 6 is one of the eigenvectors of the matrix
u(c[L0, Mo]) E SU(2). Let
e±2aie[Lo.Mo]
(0 -< e[Lo, Mo]
i)
(2.21)
be the eigenvalues of u(c[L0, M0]). Then, in (2.18),
e = +e[L0, Mo].
Thus, there exists a lagrangian solution U of (2.2) defined on the torus
V[L0, Mo] if and only if there exist three integers 1, m - Z, and n such that
ILo+1'+1N[Lo, MO]+1'NL+m'NM=n+e[Lo,MO],
Lo + I' - 2 = 1,
Mo + m' = m, where IMo < Lo. (2.22)
This assertion does not assume that 1', m', (f -
z
HM)c[L, M], and
Lgc[L, M] have negligible squares on V[L0, Mo].
U and /l will be denoted by U± and #± depending on whether (2.22)
holds with
±e[L0, Mo]. By (2.15),
(2.17), and (2.18), where e =
+e[L0, Mo], fl± satisfies (2.8), where the c±k have the values (2.9).
Assume that the squares of 1' and m' and the squares of the derivatives
of he are negligible. Then (2.22) reduces to (2.5). The integers 1, m - Z,
and n must satisfy condition (2.5)3, which is independent of l' and m'.
Since 1 and n are integers, since a is near 0, and since N > 0, (2.5)3 implies