
Understanding z-Scores 111
For Binky, there’s good news and bad news. “The good news, Binky, is that your
score of 65 is above the mean, which is also the median; you are better-looking than
more than 50% of these men. The bad news is that you are not far above the mean.
Also, the area under the curve at your score is relatively large, and thus the relative fre-
quency of equally attractive men is large. What’s worse, a relatively large part of the
distribution has higher scores.”
And then there’s Biff. “Yes, Biff, your score of 90 places you well above average in
attractiveness. In fact, as you have repeatedly told everyone, you are one of the most
attractive men around. Also, the area under the curve at your score is quite small, so
only a small proportion of men are equally attractive. Finally, the area under the curve
to the left of your score is relatively large, so if we cared to figure it out, we’d find that
you are at a very high percentile, with only a small percentage above you.”
These descriptions are based on each man’s relative standing because, considering
our “parking lot” approach to the normal curve, we literally determined where each
stands in the parking lot compared to everyone else. However, there are two problems
with these descriptions. First, they were somewhat subjective and imprecise. Second,
to get them we had to look at all scores in the distribution. However, recall that the
point of statistics is to accurately summarize our data so that we don’t need to look at
every score. The way to obtain the above information, but more precisely and without
looking at every score, is to compute each man’s z-score.
Our description of each man above was based on how far above or below the mean
his raw score appeared to be. To precisely determine this distance, our first calcula-
tion is to determine a score’s deviation, which equals . For example, Biff’s
score of 90 deviates by Likewise, Slug’s score of
35 deviates by . Such deviations sound impressive, but are they?
We have the same problem with deviations that we had with raw scores; we don’t
necessarily know whether a particular deviation should be considered large or small.
However, looking at the distribution, we see that only a few scores deviate by such
large amounts and that is what makes them impressive. Thus, a score is impressive if
it is far from the mean, and “far” is determined by how often other scores deviate
from the mean by that amount.
Therefore, to interpret a score’s location, we need to compare its deviation to all
deviations; we need a standard to compare to each deviation; we need the standard
deviation! As you know, we think of the standard deviation as our way of computing
the “average deviation.” By comparing a score’s deviation to the standard deviation,
we can describe the location of the score in terms of this average deviation. Thus, say
that, the sample standard deviation for the attractiveness scores is 10. Biff’s devia-
tion of is equivalent to 3 standard deviations, so Biff’s raw score is located
3 standard deviations above the mean. Thus, his raw score is impressive because it
is three times as far above the mean as the “average” amount that scores were about
the mean.
By transforming Biff’s deviation into standard deviation units, we have computed
his z-score. A z-score is the distance a raw score is from the mean when measured in
standard deviations. The symbol for a z-score in a sample or population is z.
A z-score always has two components: (1) either a positive or negative sign which
indicates whether the raw score is above or below the mean, and (2) the absolute value
of the z-score which indicates how far the score lies from the mean when measured in
standard deviations. So, Biff is above the mean by 3 standard deviations, so his z-score
is . If he had been below the mean by this amount, he would have .
Thus, like any raw score, a z-score is a location on the distribution. However,
the important part is that a z-score also simultaneously communicates its distance from
z 52313
130
35 2 60 5225
1because 90 2 60 5130.2130
X 2 X