NonlinearBook10pt November 20, 2007
DISSIPATIVITY THEORY FOR NONLINEAR SYSTEMS 389
(5.8) is cyclo-lossless with respect to the supply rate r(u, y) if (5.9) is satisfied
as an equality for all t ≥ t
0
and all u(·) ∈ U with x(t
0
) = x(t) = 0. Ass ume G
is completely reachable to and from the origin. Show that G is cyclo-lossless
with respect to the supply rate r(u, y) if and only if there exists a virtual
storage function V
s
(x), x ∈ D, satisfying (5.16) as an equality. Furthermore,
show that if G is cyclo-lossless with respect to the supply rate r(u, y), then
the virtual storage function V
s
(x), x ∈ D, is unique and is given by (5.44)
where x(t), t ≥ 0, is the solution to (5.7) with admissible u(·) ∈ U, t ≥ 0,
x(−T ) = 0, x(T ) = 0, and x(0) = x
0
, x
0
∈ D.
Problem 5.6. Let Q ∈ S
l
, S ∈ R
l×m
, R ∈ S
m
, and let G given
by (5.75) and (5.76) be zero-state observable and completely reachable.
Furth ermore, assume that all virtual storage functions (see Problem 5.4)
of G are continuously differentiable. Show that G is cyclo-dissipative (see
Problem 5.3) with respect to the quadratic supply rate r(u, y) = y
T
Qy
+2y
T
Su + u
T
Ru if and only if there exist functions V
s
: R
n
→ R, ℓ : R
n
→
R
p
, and W : R
n
→ R
p×m
such that V
s
(·) is continuously differentiable,
V
s
(0) = 0, and, for all x ∈ R
n
, (5.77)–(5.79) hold.
Problem 5.7. Let Q ∈ S
l
, S ∈ R
l×m
, R ∈ S
m
, and let G given by (5.75)
and (5.76) be zero-state observable and completely reachable. Furthermore,
assume that all virtual exponential storage functions (see Problem 5.4)
of G are continuously differentiable. Show that G is exponentially cyclo-
dissipative (see Problem 5.3) with respect to the quadratic supply rate
r(u, y) = y
T
Qy +2y
T
Su + u
T
Ru if and on ly if there exist functions
V
s
: R
n
→ R, ℓ : R
n
→ R
p
, W : R
n
→ R
p×m
, and a scalar ε > 0 such
that V
s
(·) is continuously differentiable, V
s
(0) = 0, and, for all x ∈ R
n
,
(5.87)–(5.89) hold.
Problem 5.8. Consider the nonlinear dynamical system G given by
(5.7) and (5.8). Define the minimum input ene rgy of G by
V
e
(x
0
) = inf
u(·), T ≥0
Z
T
0
r(u(t), y(t))dt, (5.238)
where x(t), t ≥ 0, is the solution to (5.7) with x(0) = 0 and x(T ) = x
0
. The
infimum in (5.238) is taken over all time t ≥ 0 and all admissible inputs u(·)
which drive G from x(0) = 0 to x(T ) = x
0
. It follows from (5.238) that the
minimum inpu t energy is the minimum energy it takes to drive G from the
origin to a given state x
0
. Assuming G is completely reachable, show that
V
a
(x
0
) + V
e
(x
0
) = V
r
(x
0
).
Problem 5.9. The nonlinear dynamical system (5.75) and (5.76) is
nonnegative if for every x(0) ∈ R
n
+
and u(t) ≥≥ 0, t ≥ 0, the solution
x(t), t ≥ 0, to (5.75) and the output y(t), t ≥ 0, are nonnegative, that is,