PROBLEM 10-6
Suppose a football field is to be covered by an inflatable dome that takes the
shape of a half-sphere. If the radius of the dome is 100 m, what is the volume
of air enclosed by the dome, in cubic meters? Find the result to the nearest
1000 m
3
.
SOLUTION 10-6
First, we must find the volume V of a sphere whose radius is 100 m, and then
divide the result by 2. Let p ¼ 3.14159. Using the formula with r ¼ 100 gives
this result:
V ¼ð4 3:14159 100
3
Þ=3
¼ð4 3:14159 1 ó000ó000Þ=3
¼ 4ó188ó786:667 m
3
Thus V/2 ¼ 4,188,786.667/2 ¼ 2,094,393.333 m
3
. Rounding off to the nearest
1000 m
3
, we obtain the figure of 2,094,000 m
3
as the volume of air enclosed
by the dome.
Quiz
Refer to the text in this chapter if necessary. A good score is eight correct.
Answers are in the back of the book.
1. What is the approximate surface area of the sides (not including
the base or top) of a water tower that is shaped like a right circular
cylinder, that has a radius of exactly 5 meters, and that is exactly 20
meters tall?
(a) 1571 m
2
(b) 628.3 m
2
(c) 100 m
2
(d) It cannot be determined without more information.
2. If the height of a silo that is shaped like a right circular cylinder is cut
in half while its radius remains the same, what happens to its surface
area (not including the base or the top)?
(a) It decreases to 1/2 of its previous value.
(b) It decreases to 1/4 of its previous value.
(c) It decreases to 1/8 of its previous value.
(d) It decreases to 1/16 of its previous value.
CHAPTER 10 Geometry in Space 247