Because f () is just another way of denoting r, the radius, this function tells
us that r ¼ 3. This is a circle with a radius of 3 units.
In Cartesian coordinates, the equation of the circle with radius of 3 units
is more complicated. It looks like this:
x
2
þ y
2
¼ 9
(Note that 9 ¼ 3
2
, the square of the radius.) If we let y be the dependent
variable and x be the independent variable, we can rearrange the equation
of the circle to get:
y ¼ð9 x
2
Þ
1=2
If we say that y ¼ g(x) where g is a function of x in this case, we are mistaken.
There are values of x (the independent variable) that produce two values of y
(the dependent variable). For example, when x ¼ 0, y ¼3. If we want to say
that g is a relation, that’s fine, but we cannot call it a function.
Some Examples
In order to get a good idea of how the polar coordinate system works, let’s
look at the graphs of some familiar objects. Circles, ellipses, spirals, and
other figures whose equations are complicated in Cartesian coordinates can
often be expressed simply in polar coordinates. In general, the polar direction
is expressed in radians. In the examples that follow, the ‘‘rad’’ abbreviation
is eliminated, because it is understood that all angles are in radians.
CIRCLE CENTERED AT ORIGIN
The equation of a circle centered at the origin in the polar plane is given
by the following formula:
r ¼ a
where a is a real-number constant greater than 0. This is illustrated in
Fig. 11-9.
CIRCLE PASSING THROUGH ORIGIN
The general form for the equation of a circle passing through the origin and
centered at the point (
0
, r
0
) in the polar plane (Fig. 11-10) is as follows:
r ¼ 2r
0
cos ð
0
Þ
CHAPTER 11 Graphing It 263