Габриелян О.С. Домашняя работа по химии, 9 класс
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41
Zn
0
+ 2H
+
⇒ Zn
2+
+
+
↑.
Wlmj_Zdpbxfh`ghhlg_klbd j_Zdpbyfbhggh]hh[f_gZ
L_i_jvjZkkfhljbfj_Zdpbbbhggh]hh[f_gZk ihabpbbl_hjbb
we_dljhebl bq_kdhc^bkkhpbZpbbDZd\uagZ_l_j_Zdpbybhggh]h
h[f_gZb^_llhevdh\lhfkemqZ__keb\ j_amevlZl_h[jZam_lkykeZ[h
^bkkhpbbjmxs__\_s_kl\h
GZijbf_j
ZnSO
4
+ MgCl
2
∅ MgSO
4
+ ZnCl
2
.
J_Zdpbyg_b^_lldg_h[jZamxlkyfZeh^bkkhpbbjmxsb_\_s_kl\Z
< jZkl\hj_gZoh^blkykf_kvbhgh\
ZnSO
4
+ BaCl
2
⇒ BaSO
4
↓ + ZnCl
2
.
62
−
+ Ba
2+
⇒ BaSO
4
↓.
J_Zdpbyijhl_dZ_lld%D62
4
²fZehjZkl\hjbf
<hijhk
Ihemq_gb_k_jghcdbkehlu
4
2
3
3
2
2
1
2
2
SO
H
SO
SO
S
H
FeS
S
→
→
→
.
1. S+O
2
=SO
2
↑
; 4FeS
2
H
2
t
=
2Fe
2
O
3
+8SO
2
; 2H
2
S+3O
2
t
=
2H
2
O+2SO
2
.
62
2
62
WFDW
3. SO
3
+H
2
O = H
2
SO
4
.
<hijhk
>Zgh
: V(H
2
2 fe ]962
2
e
GZclb
:
ω
\jj_
(H
2
SO
3
)
J_r_gb_AZibr_fmjZ\g_gb_ihemq_gbyk_j g bklhcdbkehlu
H
2
O+SO
2
= H
2
SO
3
.
BamjZ\g_gby\b^ghqlh^eyh[jZah\Zgbyfhev+
2
SO
3
gm`gh\aylv
fhev+
2
2b fhev62
2
GZc^_fqbkehfhev+
2
2b 62
2
:
ν
G
2
H
P+ 2
0+ 2
=
fhev
/
]
18
]
400
fhev
ν
(SO
2
) =
ν
V
)
SO(V
2
=
e
efhev
fhev
Ke_^h\Zl_evgh62
2
gZoh^blky\ g_^hklZld_b ihemqbehkvfhev
H
2
SO
3
Lh]^ZmgZkhklZehkv
ν
G
2
H
hkl
± fhev
42
2.
ω
\jj_
(H
2
SO
3
) =
)
jZ
j
(m
)
SOH(m
3
2
−
=
.
hkl
2
3
2
3
2
)
O
H
(
m
)
SO
H
(
m
)
SO
H
(
m
+
=
=
hkl
+ 62 0+ 62
+ 62 0+ 62 + 2 0+ 2
ν⋅
ν⋅ +ν⋅
=
=
fhev ]fhev
fhev ]fhev fhev ]fhev
⋅
⋅+ ⋅
= 0,095 = 9,5 %.
Hl\_l
:
ω
\jj_
(H
2
SO
3
) = 9,5 %.
<hijhk
AZibr_fj_Zdpbxkbgl_aZ62
3
:
2SO
2
+ O
2
2SO
3
.
Ij_`^_\k_]hwlZj_Zdpbyhdbkebl_evgh\hkklZgh\bl_evgZy
+
+
→
−
6
hdbke_gb_
l_ev
\hkklZgh\b
4
S
e
2
S
;
−
→
+
2
_gb_
\hkklZgh\e
hdbkebl_ev
0
2
O
2
e
4
O
.
LZd`_j_Zdpbykbgl_aZ62
3
y\ey_lkyh[jZlghcj_Zdpb_cl_hgZb^_l
h^gh\j_f_ggh\h[_klhjhguJ_ZdpbygZqbgZ_lkylhevdhijb
hlghkbl_evgh\ukhdbol_fi_jZlmjZo°Kbijhl_dZ_l\
ijbkmlkl\b_dZlZebaZlhjZieZlbguhdkb^h\\ZgZ^by`_e_aZbl^
>eykf_s_gbyjZ\gh\_kby\ijZ\hgZ^h\kihfgblvijbgpbiE_
RZl_ev_^ey]Zah\ijb\ukhdhf^Z\e_gbbj_Zdpbyb^_l\lm
klhjhgm]^_ h[sbch[t_f]Zah\f _gvr_
<gZr_fke mqZ_ke_\Zdhebq_kl\h]Zah\fhevkijZ\Z ²fhev
l_ijbm\_ebq_gbb^Z\e_gbyj_Zdpby[m^_lkf_sZlvky\ klhjhgm
h[jZah\Zgby62
3
.
<hijhk
>Zgh
: V(H
2
H fe0&X62
4
⋅
5H
2
2 ]
GZclb
:
ω
\jj_
(CuSO
4
)
J_r_gb_
: 1. m(H
2
O) = V(H
2
O)
⋅ρ
(H
2
2 fe⋅]fhev ]
GZc^_ffZkkmjZkl\hjZkheb
Ph[s P+
2
O) + m(CuSO
4
⋅
5H
2
O) = 5000
]
GZc^_ffZkkmkmevnZlZf_^b[_a\h^gh]h
m(CuSO
4
) = m(CuSO
4
⋅
5H
2
O)
⋅ω
\ &X62
⋅
GH
(CuSO
4
) =
= m(CuSO
4
)
⋅
0U&X62
0U&X62 0U+ 2
+
]⋅
+
]⋅ ]
Lh]^ZfZkkh\Zy^hey&X62
4
\ jZkl\hj_
ω
(CuSO
4
) =
)
h[s
(m
)
CuSO(m
4
=
]
5500
320
≈
0,058 = 5,8 %.
Hl\_l
:
ω
(CuSO
4
) = 5,8 %.
43
<hijhk
<gbfZl_evgh jZkkfhljbl_ ko_fm ijbf_g_gby k_jghc dbkehlu
jbk gZkljb ihiulZcl_kv kZfbhl\_lblvgZwlhl\hijhk
§ 23
:ahl
<hijhk
Z0J
+ N
2
= Mg
3
N
2
²gbljb^fZ]gby
0J H 0J
1H1
+
−
−=
+=
[KZ
+ N
2
= Ca
3
N
2
²gbljb^dZevpby
&D H &D
1H1
+
−
−=
+=
\$O
+ N
2
= 2AlN
²gbljb^Zexfbgby
$O H $O
1H1
+
−
−=
+=
< ijh^mdlZo j_Zdpbc bhgguc lbi obfbq_kdhc k\yab b bhggZy
djbklZeebq_kdZyj_r_ldZ
Gbljb^uf_lZeeh\e_]dh]b^jhebamxlkyk \u^_e_gb_fZffbZdZ
Mg
3
N
2
+ 6H
2
O 3Mg(OH)
2
↓
+ 2NH
3
↑
;
<hijhk
1
→
/L
1
→
1+
→
12
→
12
→
+12
1. N
2
+ 6Li = 2Li
3
N;
1H1
−
+→
2. Li
3
N + 3H
2
O = 3LiOH + NH
3
↑
; Li – 1
H
→
Li
+
;
3. 4NH
3
H
2
cat
=
4NO
↑
+ 6H
2
O;
4. 2NO + O
2
= 2NO
2
;
5. 4NO
2
+ 2H
2
O + O
2
= 4HNO
3
.
<hijhk
JZkkfhljbfke_^mxsmxj_Zdpbx
2NO + O
2
∅
2NO
2
+ Q.
Ij_`^_\k_]hwlZj_Zdpbyhdbkebl_evgh\hkklZgh\bl_evgZy
hdbke_gb_
\hkklZgh\bl_ev
1H 1
++
− →
;
−
→
+
2
_gb_
\hkklZgh\e
hdbkebl_ev
0
2
O
2
e
4
O
.
44
LZd`_j_Zdpbykbgl_aZ12
2
y\ey_lkyh[jZlghcj_Zdpb_cl_hgZ
b^_lh^gh\j_f_ggh\h[_klhjhguLd\ j_ZdpbbmqZkl\mxl]Zaulh
fufh`_fijbf_gblvijbgpbiE_RZl_ev_
<gZr_cj_Zdpbbdhebq_kl\hfhev]Zah\ke_ \Z[hevr_q_fkijZ\Z
Lh]^Zijbm\_ebq_gbb^Z\e_gbyjZ\gh\_kb_kf_klblky\ijZ\h
< ijyfhcj_Zdpbb\u^_ey_lkyl_iehke_^h\Zl_evghijb
mf_gvr_gbbl_fi_jZl mjujZ\gh\_kb_kf_kl blky\ijZ\h
<hijhk
Z1+
3
+ 5O
2
= 4NO
↑
+ 6H
2
O
1H1
2H2
−+
−
−=
+=
[1+
3
+ 3O
2
⇒
2N
2
↑
+ 6H
2
O
1 H 1
2H2
−
−
−=
+=
.
<hijhk
>Zgh
: m(NH
4
NO
2
]ωijbf_kb
%.
GZclb
: V(N
2
),
ν
(H
2
O)
J_r_gb_GZc^_ffZkkmkheb[_aijbf_k_c
m(NH
4
NO
2
)=m(NH
4
NO
2
ij±P1+
4
NO
2
)
⋅ω
ij
]±]⋅
0,012=19,76
]
AZibr_fmjZ\g_gb_j_Zdpbb
m]
]
W
oe
fhev
fhev
fhev
0
]fhev 9 ]fhev F ]fhev
P
]P ]
9
]
1+ 12 1+2
GZc^_f91
2
b P+
2
O):
] ²e
] ²oe
o
19,76 22,4
64
⋅
e91
2
e
] ²]
] ²m]
y =
19,76 36
64
⋅
= 11,115
]P+
2
2 ]
Lh]^Zν
(H
2
O) =
P+ 2
0+ 2
=
]
]fhev
fhev
Hl\_l
: V(N
2
eν
(H
2
2 fhev
45
§ 24
:ffbZd
<hijhk
:ffbZd e_]dh k`b`Z_lky ijb h[uqghf ^Z\e_gbb b l_fi_jZlmj_ ±
33,4°
KZijbbkiZj_gbb`b^dh]h]ZaZbahdjm`Zx s_ckj_^uih]ehsZ_lky
fgh]hl_ie Zihwlhfmhgijbf_gy_lky \ oheh^bevguo mklZgh\dZo
:ffbZdhq_gvohjhrhjZkl\hjbf\\h^_ jZkl\hjZffbZdZ
gZau\Z_lkygZrZlujgufkibjlhfb bkihevam_lky\ f_^bpbg_
2
<hijhk
<h^hjh^gZyk\yav ²wlhobfbq_kdZyk\yavf_`^mZlhfZfb\h^hjh^Z
b ZlhfZf bkb evghwe_dljhhljbpZl_evguowe_f_glh\nlhj
dbkehjh^Zahl<h^hjh^gZyk\yavh[jZam_lkyh[uqghf_`^m^\mfy
khk_^gbfbfhe_dmeZfbGZijbf_jhgZh[jZam_lkyf_`^m
fhe_dmeZfb\h^ukibjlh\nlhjh\h^hjh^ZZffbZdZ
Wlhhq_gvkeZ[Zyk\yav ²ijbf_jgh\ jZakeZ[__dh\Ze_glghc
;eZ]h^Zjy _c g_dhlhju_ gbadhfhe_dmeyjgu_ \_s_kl\Z h[jZamxl
ZkkhpbZlu qlh ijb\h^bl d ih\ur_gbx l_fi_jZlmj ieZ\e_gby b
dbi_gby\_s_kl\
:ghfZevgh \ukhdb_ l_fi_jZlmju ieZ\e_gbyb dbi_gby oZjZdl_jgu
^ey\h^u_kebjZkkfZljb\Zlv\h^hjh^gu_ kh_^bg_gby9, ]jmiiu<k_
\h^hjh^gu_kh_^bg_gby9,]jmiiudjhf_\h^uy\eyxlky]ZaZfb
Hq_gv\Z`gmxjhevb]jZ_l\h^ hjh^gZyk\yav\ fhe_dmeZo\Z`g_crbo
^ey`b\uokms_kl\kh_^bg_gbc ²[_edh\b gmde_bgh\uodbkehl
3
<hijhk
>hghjghZdp_ilhjgZyk\yav ²wlhhkh[uc\b^obfbq_kdhc k\yab
dhlhjZy\hagbdZ_lg_aZkq_lkiZjb\Zgbyg_iZjguowe_dljhgh\ZaZ
kq_lk\h[h^ghcwe_dljhgghciZjuh^gh]hZlhfZb k\h[h^ghcyq_cdb
^jm]h]h
4
<hijhk
Kl_i_gvhdbke_gbyZah lZ\ oehjb^_Zffhgby1+
4
Cl:
1+ &O
−
.
Kl_i_gvhdbke_gbyZah lZ\ gbljZl_Zffhgby1+
4
NO
3
:
1+ 12
−+
.
<hijhk
3CuO + 2NH
3
= N
2
+ 3Cu + 3H
2
O.
&X H &X
1 H 1
+
−
+=
−=
.
2
>eyhl\_lZbkihevah\Zekymq_[gbdklj
3
>eyhl\_lZbkihevah\Zekymq_[gbdklj
4
>eyhl\_lZbkihevah\Zekymq_[gbdklj
46
<hijhk
:ffbZd ijhy\ey_l lhevdh \hkklZgh\bl_evgu_ k\hckl\Z ld Zahl
gZoh^blky \kZfhc gbadhc kl_i_gb hdbke_gby bg_ fh`_l [hevr_
ijbgbfZlvwe_dljhgu
§ 25
KhebZffhgby
<hijhk
Z1+
4
)
2
SO
4
+ BaCl
2
= BaSO
4
↓
+ 2NH
4
Cl; SO
4
2–
+ Ba
2+
= BaSO
4
↓
.
[1+
4
Cl + AgNO
3
= AgCl
↓
+ NH
4
NO
3
; Ag
+
+ Cl
–
= AgCl
↓
.
<hijhk
Z1+
4
)
2
CO
3
+H
2
SO
4
=(NH
4
)
2
SO
4
+H
2
O+CO
2
↑
; CO
3
–
2
+2H
+
=H
2
O+CO
2
↑
.
[1+
4
)
2
CO
3
+2NaOH=Na
2
CO
3
+2NH
3
↑
+2H
2
O; NH
4
+
+OH
–
=NH
3
↑
+H
2
O.
\1+
4
)
2
CO
3
+ CaCl
2
= CaCO
3
↓
+ 2NH
4
Cl; CO
3
2–
+ Ca
2 +
= CaCO
3
↓
.
]1+
4
)
2
CO
3
W
CO
2
↑
+ 2NH
3
↑
+ H
2
O
↑
.
<hijhk
(NH
4
)
3
PO
4
²nhknZlZffhgby
(NH
4
)
2
HPO
4
²]b^jhnhknZlZffhgby
NH
4
H
2
PO
4
²^b]b^jhnhknZlZffhgby
(NH
4
)
3
PO
4
∅
3NH
4
+
+ PO
4
3–
.
(NH
4
)
2
HPO
4
∅
2NH
4
+
+ H
+
+PO
4
3–
(NH
4
)H
2
PO
4
∅
NH
4
+
+ 2H
+
+ PO
4
3–
.
<hijhk
N
2
→
1
NH
3
→
2
(NH
4
)
2
HPO
4
→
3
NH
4
Cl
→
4
NH
4
NO
3
.
1. N
2
+ 3H
2
WSFDW
-
2NH
3
↑;
2. H
3
PO
4
+ 2NH
3
= (NH
4
)
2
HPO
4
;
3. (NH
4
)
2
HPO
4
G&O 1+
4
Cl + H
3
JH
4
;
4. NH
4
Cl + AgNO
3
= AgCl↓ + NH
4
NO
3
.
<hijhk
>ZghP((NH
4
)
2
SO
4
d]
GZclb91+
3
), m(NH
3
)
J_r_gb_GZc^_ffZkkh\mx^hexZffbZdZ\kmevnZl_Zffhgby
1+ 62
ω
(NH
3
)=
01+
01+ 62
=
fhev
/]132
fhev
/
]17
2
⋅
=0,2576=25,76 %.
GZc^_ffZkkmZffbZdZg_h[oh^bfh]h^eyihemq_gbyd]
(NH
4
)
2
SO
4
:
m(NH
3
) = m((NH
4
)
2
SO
4
)⋅ω(NH
3
d]⋅ d]
GZc^_fh[t_fZffbZdZ
47
V(NH
3
)=
ν
(NH
3
)
⋅
V
ν
=
P1+
01+
⋅
V
ν
=
]
]fhev
⋅
⋅efhev e
f
3
.
Hl\_l
: m(NH
3
d]91+
3
f
3
.
§ 26
Dbkehjh^gu_kh_^bg_gbyZahlZ
<hijhk
:ahlg Zy dbkehlZ g_ h[jZam_l dbkeuo khe_c ld hgZ h^ghhkgh\ gZy b
bf__l\k_]hh^bgZlhf\h^hjh^Zdhlhjucb hl^Z_lijbh[jZah\Zgbbkheb
<hijhk
Z&X2+
2
+ 2HNO
3
=2H
2
O + Cu(NO
3
)
2
; Cu(OH)
2
+ 2H
+
=Cu
2+
+ 2H
2
O;
[)H
2
O
3
+ 6HNO
3
= 2Fe(NO
3
)
3
+ 3H
2
O; Fe
2
O
3
+ 6H
+
= 2Fe
3+
+ 3H
2
O.
\1D
2
CO
3
+2HNO
3
=2NaNO
3
+ H
2
O + CO
2
↑
; CO
3
2–
+ 2H
+
=H
2
O +
CO
2
↑
.
<hijhk
Na
2
SiO
3
+ 2HNO
3
= 2NaNO
3
+ H
2
SiO
3
↓
; SiO
3
2–
+ 2H
+
= H
2
SiO
3
↓
.
<hijhk
1) 3Cu + 8HNO
jZa[
= 3Cu(NO
3
)
2
+ 2NO
↑
+ 2H
2
O,
&X H &X
1H 1
−
.
2) Cu + 4HNO
3(
dhgp
)
= Cu(NO
3
)
2
+ 2NO
2
↑
+ 2H
2
O
&X H &X
1H 1
−
<hijhk
I. N
2
→
1
NO
→
2
NO
2
→
3
HNO
3
.
1. N
2
+ O
2
= 2NO,
1H1
2H2
+
−
−=
+=
.
2. 2NO + O
2
= 2NO
2
,
1H1
2H2
++
−
−=
+=
.
3. 4NO
2
+ O
2
+ 2H
2
O = 4HNO
3
,
1H1
2H2
++
−
−=
+=
.
II. NH
3
1
→
NO
2
→
NO
2
3
→
HNO
3
.
1. 4NH
3
+ 5O
2
= 4NO + 6H
2
O,
48
1H1
2H2
−
+
−
−=
+=
.
MjZ\g_gbyb kfhljb\ur_
<hijhk
>Zgh
: V(NO
2
f
3
;
ω
(HNO
3
) = 68 %.
GZclbP+12
3
)
J_r_gb_AZibr_f mjZ\g_gb_j_Zdpbbihemq_gbyZahlghcdbkehlu
e
o]
fhev
fhev
9
efhev
0
]fhev
P
]
9
e
12 2+2 +12
ν
⋅
89,6
e
— 252
134,4
⋅
10
3
e ²o]
o
] e
e
⋅⋅
d]
GZc^_ffZkkmjZkl\hjZZahlghcdbkehlu
m(HNO
3
) =
)
HNO(
x
3
ω
=
379
d]
0,68
= 555,9
d]
;
Hl\_l
: m(HNO
3
) = 555,9
d]
<hijhk
>Zgh
: m(NaNO
3
]92
2
e
GZclbPijbf_kb
J_r_gb_AZibr_fmjZ\g_gb_j_Zdpbb
e
o] W
fhev
fhev
9
efhev
0
]fhev
P
]
9
e
1D12 1D12 2
↑
] ²e
o]²e
o
⋅
]
m
qbklZy
(NaNO
3
]
GZc^_ffZkkmijbf_kb
Pij P1D12
3
)–m
qbklZy
(NaNO
3
]±] ]
ω
ij
=
ij
k_e
P
P
=
beb
Hl\_l
:
ω
ij
= 25%.
<hijhk
Kf\hijhk,,
49
§ 27
Nhknhjb_]hkh_^bg_gby
<hijhk
1. Na
3
PO
4
²nhknZlgZljby
Na
3
PO
4
= 3Na
+
+ PO
4
3–
;
2. Na
2
HPO
4
²]b^jhnhknZlgZljby
Na
2
G32
4
= 2Na
+
G
+
+ PO
4
3–
;
3. NaH
2
PO
4
²^b]b^jhnhknZlgZljby 1DG
2
PO
4
= Na
+
G
+
+ PO
4
3–
.
<hijhk
J
→
1
Mg
3
P
2
→
2
PH
3
→
3
P
2
O
5
→
4
H
3
PO
4
→
5
Ca
3
(PO
4
)
2
.
1.
J
+ 3Mg
t
=
Mg
3
P
2
,
3H 3
0J H 0J
−
,
2. Mg
3
P
2
+ 6H
2
O = 3Mg(OH)
2
↓
+ 2PH
3
↑
.
3. 2PH
3
+ 4O
2
= P
2
O
5
+ 3H
2
O,
3H3
2H2
−+
−
−=
+=
,
4. P
2
O
5
+ 3H
2
O = 2H
3
PO
4
;
5. 2H
3
PO
4
&DHG
2
= Ca
3
(PO
4
)
2
↓
+ 6H
2
H
<hijhk
3P + 5HNO
3
+ 2H
2
O = 3H
3
PO
4
+ 5NO
↑
,
3H3
1H1
+
++
−=
+=
.
<hijhk
>Zgh
: m(Ca
3
(PO)
4
ij ]ωij
%, W = 80 %.
GZclb
: m(P)
J_r_gb_GZc^_ffZkkmkheb[_aijbf_kb
m(Ca
3
(PO
4
)
2
) = m(Ca
3
(PO
4
)
2
ij±P&D
3
(PO
4
)
2
ij⋅ωij
]± ] ⋅ ]
AZibr_fmjZ\g_gb_j_Zdpbb
o]
]
fhev
fhev
0
]fhev
0
]fhev
P
]
P
]
&D 32 6L2 & &D6L2 3
↑
] ²]
] ²o]
o
⋅
]
m(P)
l_hj
]
GZc^_ffZkkmnhknhjZdhlhjZyihemqbeZkv\oh^_j_Zdpbb
m(P)
ijZdl
= m(P)
l_hj
⋅: ]⋅ ]
50
Hl\_l
: m(P)
ijZdl
]
<hijhk
>ZghP3 ]ωij
%,
ω
(H
3
PO
4
) = 80 %.
GZclb
: m
jjZ
(H
3
PO
4
)
J_r_gb_GZc^_ffZkkmnhknhjZ[_aijbf_kb
m(P) = m(P
ij
– m(P
ij⋅ωij ]
– 31
⋅ ]
Bah^gh]hfhevnhknhjZfh`ghihemqblvjh\ghh^bgfhev
nhknhjghcdbkehlu
ν
(H
3
PO
4
)=
ν
(P)=
P3
03
⇒ν
(H
3
PO
4
)=
P3
03
=
]
31
]
45,29
=0,95
fhev
Lh]^ZP+
3
PO
4
)=M(H
3
PO
4
)
⋅ν
(H
3
PO
4
]fhev⋅fhev ]
FZkkZjZkl\hjZnhknhjghcdbkehlujZ\gZ
PjjZ+
3
PO
4
) =
)
POH(
)
POH(m
4
3
4
3
ω
=
]
]
Hl\_lPjjZ+
3
PO
4
]
<hijhk
>ZghPjjZ+
3
PO
4
]ω
1
(H
3
PO
4
) = 5
PJ
2
H
5
]
GZclb
:
ω
2
(H
3
PO
4
)
J_r_gb_AZibr_fmjZ\g_gb_j_Zdpbbihemq_gbynhknhjghc
dbkehlu
G
2
H J
2
H
5
G
3
JH
4
.
BamjZ\g_gby\b^ghqlhbafhevJ
2
H
5
ihemqZ_lkyfhevG
3
JH
4
.
GZc^_ffZkkmnhknhjghcdbkehluihemqb\r_cky\oh^_j_Zdpbb
ν
(H
3
PO
4
) = 2
ν
(P
2
O
5
) = 2
⋅
P3 2
03 2
= 2
⋅
]
]fhev
fhev
m(H
3
PO
4
) =
ν
(H
3
PO
4
)
⋅
M(H
3
PO
4
fhev⋅]fhev ]
GZc^_fkdhevdh[uehnhknhjghcdbkehlu\ jZkl\hj_
m(H
3
PO
4
PjjZ⋅ω
1
(H
3
PO
4
) = 980
⋅ ]
GZc^_fgh\mxfZkkh\mx^hexdbkehlu\ jZkl\hj_
ω
2
(H
3
PO
4
) =
h[s
P+ 32
PjjZP32
−+
=
152
980
49
72,209
+
+
= 0,2286.
Hl\_l
:
ω
2
(H
3
PO
4
) = 22,86 %.
<hijhk
:DhgZg>hce \k\h_f ijhba\_^_gbb g_ mq_e obfbq_kdbo k\hckl\
nhknhjZ >Z\Zcl_ ih^mfZ_f \f_kl_ Nhknhj k\_lblky \ l_fghl_
ke_^h\Zl_evgh wlh [_euc nhknhj ld djZkguc nhknhj g_ k\_lblky
\hh[s_ >Ze__ [_euc nhknhj hq_gv y^h\bl b bkihevah\Zlv _]h klhev