10.9 Summary of Important Potential Flows 299
With this the position coordinates of the free stagnation point result as:
ϕ
s
=
3π
2
and
r
s
R
=
Γ
4πU
0
R
⎡
⎣
1+
$
1 −
4πU
0
R
Γ
2
⎤
⎦
. (10.107)
The negative sign of the root in the solution for r
s
wasomittedinthe
statement of the position coordinates for the free stagnation point, as this
would lead to a radius which is located inside the cylinder surface area. As
only the flow around the cylinder is of concern, this second solution of the
square equation for r
s
is of no interest in the considerations presented here.
Moreover, it was also excluded from the solution for the position coordi-
nates of the free stagnation point that the angle ϕ
s
also has a solution for
π
2
. The reason for this is that for
Γ
4πU
0
R
= 1 the stagnation point appears
as a solution only in the lower half of the cylinder surface area. Inclusion
of the solution for ϕ
s
=
π
2
would mean that a small increase in the circu-
lation, to an extent that the standardized circulation is given a value larger
than 1, would lead to a jump of the stagnation point from the lower to the
upper half of the flow. Considerations on the stability of the position of the
stagnation points show, however, that only the lower stagnation point, i.e
ϕ
s
=
3π
2
, can exist as a stable solution. Because of the superposition of the
flow around a cylinder with a potential vortex, a flow field has come about,
which again is symmetrical concerning the y-axis. With this outcome of the
above considerations it is in turn determined that, owing to the flow around
the cylinder, the cylinder surface area obtains no resulting force acting in the
flow direction, i.e. no resistance force occurs because of the flow. Owing to
the imposed circulation, an asymmetric flow with respect to the x-axis, has
come about, however, and this leads to a buoyancy force, i.e. to a resulting
force on the cylinder, directed upwards. As the velocity component on the
upper side of the cylinder is larger than that on the lower side, because of
the Bernoulli equation a pressure difference results, with low pressure on the
upper side. This causes a flow force directed upwards. The quantitative deter-
mination of this force requires integral relationships to be applied as derived
in Sect. 10.10.
10.9 Summary of Important Potential Flows
In the preceding sections, a number of potential flows were discussed which
are known as basic potential flows and whose treatment give an insight into
the fluid flow processes that occur. In Table 10.1, further analytical functions
are stated, in addition to the already extensively discussed examples, which
can be used for the derivation of potential and stream functions and the
corresponding velocity fields of potential flows. By equating the indicated