374
XII.
Non-negative
solutions
in
l::r.
The
case
1 <p<2
IDu
n
l
p
-
2
Du
n
D('I/1
-
u)+
= ID(Un "
k)IP-2
D(u
n
"k)D('I/1 -
U"
k)+
=
(IDu
n
.kI
P
-
2
DUn.k
-IDuklp-2
DUk)
.D('I/1
-
Uk)
+ IDuI
P
-
2
Du·D('I/1 - u)+.
By
a calculation similar
to
that in Lemma 5.2 and leading to (5.6) we have
Therefore taking into account Lemma
12.1 and letting
n-+oo
in (12.6) gives
t
j j
{Ut('I/1
-
u)+
+ IDulp-2
Du·D
('1/1
- u)+} dxdr =
0,
·a
N
o
for all
'1/1
EX
loc
(ET)' It remains
to
prove that U takes the initial datum U
o
in the
sense
of
Lloc(RN) and that
ueS·.
12-(i). Continuity
in
Lloc(RN) at t=O
Fix p > 0 and let u
o
•
e
be
a net
of
functions satisfying
{
uo.e
==
0,
u
o
•
e
--+
u
o
,
for Ixl > 4p
in
L1
(K
2p
)'
Such a family
can
be
constructed
by
fllSt defining a function that coincides with
U
o
in K
3p
and zero otherwise and then
by
mollifying the function so obtained.
Let also
U
e
be
the unique solution
of
(1.1) with initial datum u
o
•
e
•
We take the
difference
of
(8.I)n
and the equation satisfied by
Ue.
In the p.d.e.
so
obtained take
the testing function
tp =
[(un
- u
e
)+
+
6l
a
(
where
(1,6
e (0,1) and
x-«x)
is the usual cutoff function in K
2p
that equals one
on
Kp.
We perfonn an integration by parts and let
6-+0,
8-0,
(1-0.
to
obtain
j(Un(t) - ue(t»+dx
~
j(Uo.n - uo.e)+dx
Kp
K2p
t
+
2;
j j (IDunIP-1 + IDueIP-1) dxdr.
OK2p
We use (8.4), interchange the role
of
Un
and
Ue
and, for t > 0 fixed, let n -+
00.
This gives