IV.2. Limit sets, attractors and Lyapunov functions 139
x
U
!.x/
Figure IV.6. Proposition IV.8 (ii).
(iii) !.x/ is a connected set.
The limit set !
.x/ has analogous properties as the time tends to minus infinity.
Proof. If y 2 !.x/, there exists a sequence t
n
!1satisfying x t
n
! y and
using the continuity of the flow we conclude for every real number t,
y t D
lim
n!1
x t
n
t D lim
n!1
x .t
n
C t/:
Since t
n
C t !1as n !1we find y t 2 !.x/, so that the limit set is indeed
invariant under the flow.
(i)We take a sequence t
n
!1. Then the sequence .xt
n
/
n1
lies in the compact
set
O
C
.x/, so that there exists a convergent subsequence whose limit belongs to
!.x/, in view of the definition of a limit set. Consequently, the limit set !.x/ is not
empty. Since !.x/ is closed and contained in the compact set
O
C
.x/, the limit set
!.x/ is compact.
(ii) We shall prove that for every sequence t
n
!1and for every open neigh-
borhood U of !.x/ there exists an integer n
U
, satisfying x t
n
2 U for all n n
U
.
Arguing by contradiction we assume that x t does not converge to !.x/. Then
there exists an open neighborhood U of !.x/ and a sequence t
n
!1satisfying
x t
n
… U for all n. Since O
C
.x/ \ U
c
is compact, there exists a convergent
subsequence x t
j
! y 2 U
c
. Its limit satisfies y 2 !.x/ \ U
c
, in contradiction
to the assumption U !.x/.
(iii) In order to prove the statement in (iii), we argue again by contradiction and
assume the existence of two closed sets !
1
;!
2
¤;satisfying !.x/ D !
1
[ !
2
and !
1
\!
2
D;. With !.x/ also the sets !
1
and !
2
are compact. Therefore, there
exist open sets U
1
;U
2
R
n
satisfying
!
1
U
1
;!
2
U
2
;U
1
\ U
2
D;:
The set U ´ U
1
[ U
2
is an open neighborhood of !.x/. In view of (ii),
x t 2 U; t t
U