III.5. Torus automorphisms 119
This holds true for every j 2 Z
2
and setting B ´ A
T
, we therefore deduce
f
j
D f
Bj
D f
B
2
j
DDf
B
n
j
D;j2 Z
2
:
For f belonging to L
1
we know that
f
k
! 0; jkj!1;
where jkjD
q
k
2
1
C k
2
2
. Hence, if the sequence jB
n
j j for every fixed 0 ¤ j 2 Z
2
is unbounded, then f
j
D 0 for all j ¤ 0 and consequently the function f is
constant almost everywhere.
The sequence jB
n
j j is indeed unbounded, because the set fB
n
j j n 2 Ng is
an infinite set, since for j ¤ 0 all these points are different. If they were not, we
would find an integer m 2 N satisfying B
m
j D j , so that B
m
would have an
eigenvalue 1. This, however, is not possible, since B and hence B
m
is a hyperbolic
map. We have demonstrated that every invariant integrable function is constant
almost everywhere. Consequently, due to Proposition I.17 the diffeomorphism '
A
is ergodic.
(iii) The statement (iii) follows from the ergodicity of '
A
(Proposition I.21).
(iv) Since A is an invertible matrix over the ring Z,wehaveA.Z
2
/ D Z
2
, hence,
due to the linearity A.
1
k
Z
2
/ D
1
k
Z
2
. On the torus we conclude '
A
.p.
1
k
Z
2
// D
p.A.
1
k
Z
2
// D p.
1
k
Z
2
/. This set is finite (since it corresponds bijectively to the set
Œ0; 1/ Œ0; 1/ \
1
k
Z
2
), hence '
A
is a permutation of this set and the orbits in
1
k
Z
2
are all periodic. The points p.
1
k
Z
2
/ with k 2 N lie densely on the torus. We claim
that we have found already all the periodic points. Indeed, if p.z/ is a periodic
point of '
A
, where z D .x; y/ 2 R
2
, then there exist an integer n and an integer
vector k D .k
1
;k
2
/ 2 Z
2
such that A
n
z D z Ck and hence .A
n
1/z D k. Since
A
n
does not have an eigenvalue 1, this equation has a unique solution z D .x; y/,
given by a rational function of the integer matrix elements of A
n
and of k
1
;k
2
and
therefore x; y 2 Q are rational, as claimed.
(v) The statement (v) has been proved previously.
(vi) We assume that g is a C
1
perturbation of '
A
, so that g D '
A
COg where
the map Og is small in the C
1
-sense. We consider the homotopy g
t
D '
A
C t Og,
connecting g
0
D '
A
with g
1
D g and we choose a lift G of the end point g D g
1
,
so that G.0/ is near 0. We then lift the homotopy to a homotopy G
t
. We may
assume that G
0
D A. From
G
0
.x C j/ G
0
.x/ D A.x C j/ Ax D Aj 2 Z
2
;z2 Z
2
it follows, since Z
2
R
2
is discrete, that
G
t
.x C j/ G
t
.x/ D Aj 2 Z
2