286 Circulation and vorticity theorems
since the potential vorticity is conserved. From this relation we my explain qual-
itatively the behavior of the trajectory of an air parcel as it crosses the mountain
barrier. Suppose that at position A there is straight-line flow in the eastward di-
rection without any shear of the horizontal wind vector. We write the potential
vorticity in Cartesian coordinates
ζ
θ
=
∂v
∂x
θ
−
∂u
∂y
θ
(10.95)
where the partial derivatives are evaluated along the θ-surface. Thus we immedi-
ately recognize that ζ
θ
(A) = 0. When the air parcel begins to cross the mountain
range, the difference in pressure between the isentropic surfaces decreases so that
the relative vorticity over the mountain range must be negative in order to conserve
absolute vorticity; see part (b) of Figure 10.2. This results in anticyclonic curva-
ture of the trajectory in the northern hemisphere. After the air parcel has crossed
the mountain the difference in pressure between the two isentropic surfaces has
returned to its original value. Without the effect of the changing Coriolis parameter
the air parcel would have reached the position C, where straight line flow would
result due to the assumed symmetry of the mountain barrier. This means that the
straight westerly flow has changed to a flow from the north-west. So far we have
assumed that the Coriolis parameter f remains constant. However, as the air parcel
is moving south, the Coriolis parameter is decreasing, thus causing the relative
vorticity to become positive so that the resulting trajectory would have a positive
curvature at C due to the conservation principle. The formation of the lee-side
trough is observed quite regularly to the east of the Rocky Mountains; see Bolin
(1950). Further details are given, for example, by Holton (1972) and Pichler (1997).
10.4.6 Helmholtz’s baroclinic vortex theorem
The general vortex theorem in the absolute system (10.54) can be used to deduce
Helmholtz’s famous vortex theorem, which is the starting point for the derivation
of some circulation laws to be discussed in detail. On replacing ψ by (x, y,z)
successively in (10.54) with (∇x = i, ∇y = j, ∇z = k)and(˙x = u
A
, ˙y = v
A
, ˙z =
w
A
) we obtain
d
dt
(α ∇×B
A
· i) −α ∇×B
A
·∇u
A
= 0
d
dt
(α ∇×B
A
· j) −α ∇×B
A
·∇v
A
= 0
d
dt
(α ∇×B
A
· k) −α ∇×B
A
·∇w
A
= 0
(10.96)