5.8 Integration of Cooperativities Due to Apolar-Polar and Charge-Charge Repulsion
201
Figure 5.30, in poly(GEGIP) the Glu residues
are separated by four residues, -EGIPGE-, and
the pKa shift due to charge-charge repulsion is
>0.35 pH units. The charge-charge repulsion
component of the pKa shift for -EPGE- is
expected to be greater than for -EGIPGE-.
Accordingly, in the titration curve of Model
Protein I, when compared with those of Model
Proteins i, ii, iii, iv, and v, the differential effects
of charge-charge and apolar-polar repulsion
become apparent, and an iterative fitting
process using Equation (5.23) should allow
determination of AGcc and AGap in this mixed
case.
In doing so the recognition of the residual
pKa shift after complete unfolding, shown in
Figure 5.31, should also be delineated.
5.8.5.4 Positive Cooperativity as a
Fundamental Property of the Competition
for Hydration Between Apolar
(Hydrophobic) and Polar (e.g..
Charged) Species
From the analysis of the acid-base titration
data in Figures 5.30 through 5.34, positive coop-
erativity results from the apolar-polar repul-
sive free energy of hydration, that is, from the
competition for hydration between apolar
(hydrophobic) and polar (e.g., charged) species.
The general statement can be that the appear-
ance on the scene of the first polar, for example,
charged, species must do the work of destruc-
turing hydrophobic hydration in order to
achieve adequate hydration for
itself.
To put this into perspective, consider again
the Gibbs free energy for solubility, AG(solu-
bility) = AH - TAS, and recall the discussion of
Butler's findings (see section 5.1.3.3), where
insolubiUty results from the formation of too
much hydrophobic hydration. Too much hydro-
phobic hydration causes the positive (-TAS)
term to become larger than the negative
(exothermic) AH term, that is, when AG(solu-
bility) becomes positive and solubility is lost.
The insolubiUty comes in the form of the asso-
ciation of a pair of hydrophobic domains.
However, the pair of domains undergoes disso-
ciation and association fluctuations. Now, a
polar species can emerge (e.g., COOH -^
COO") proximal to an opening fluctuation, if it
can achieve adequate hydration by destructur-
ing the hydrophobic hydration. In doing so it
lowers the magnitude of the positive (-TAS)
term sufficiently to allow the dissociation to
stand. Even though there may yet be substan-
tial hydrophobic hydration covering the sur-
faces of the previously paired hydrophobic
domains, there is additional water, and the
emergence of the second polar species achieves
its hydration without having to destructure
quite so much hydrophobic hydration, and its
equilibrium constant is more favorable. This is
the description of positive cooperativity at the
molecular level arising from an apolar-polar
repulsive free energy of hydration.
To the best of my knowledge, the hemoglobin
oxygenation curve is historically the first
example of a biologically essential positive
cooperativity. Because of this, it becomes an
important objective to explore the phenome-
nology of hemoglobin's positive cooperativity
and compare it with that of the consilient
mechanism due to an apolar-polar repulsive
free energy of hydration (as is done in
Chapter 7) and, in fact, to do so for a number of
protein-based machines that exhibit positive
cooperativity.
5.8.5.5 Evaluation of [(dAG/da)Tjap Within
the Single Polymer, Model Protein v
From the plot in Figure 5.31A of the titration
of Model Protein v, the pKa of the first car-
boxyls to ionize may be taken as 7.0, whereas
that of the last carboxyls to ionize is about 5.7.
Therefore, in the process of driving hydropho-
bic disassociation of a relaxation or, inversely,
in the process of driving hydrophobic associa-
tion of a contraction, the pKa shifts by some
1.3 pH units. By Equation (5.13), AGap
= 2.3 RT ApKa - 2.3 x 1.987 x 310 x 1.3
= 1.8kcal/mole-carboxyl. Now, because
AGap = J[(9AG/3a)T]apda, we have that
/[(3AG/3a)T]apda « 1.8 kcal/mole-carboxyl. This
is an example wherein only the apolar-polar
repulsive free energy of hydration is relevant,
as the presence of a Glu (E) residue every 30
residues does not give rise to charge-charge
repulsion in the unfolded, state. Also, when
totally unfolded the carboxyl pKa is still shifted