5. Compressible fluid motion 453
One implication of (5.34) is the following. Let S be an oriented surface in ,
with boundary C ;letS.t/ be the image of S under F
t
,andC.t/ the image of C ;
then (5.34) yields
(5.36)
Z
S.t/
Q
.t/ D
Z
S
Q
.0/:
Since
Q
D d Qv, this implies the following:
Kelvin’s circulation theorem.
(5.37)
Z
C.t/
Qv.t/ D
Z
C
Qv.0/:
We take a look at some phenomena special to the case dim D n D 3,where
the vorticity is a vector field on , for each t.Fixt
0
and consider D .t
0
/.
Let S be an oriented surface in , transversal to .Avortex tube T is defined
to be the union of orbits of through S, to a second transversal surface S
2
.For
simplicity we will assume that none of these orbits ends at a zero of the vorticity
field, though more general cases can be handled by a limiting argument.
Since d
Q
D d
2
Qv D 0, we can use Stokes’ theorem to write
(5.38) 0 D
Z
T
d
Q
D
Z
@T
Q
:
Now @T consists of three pieces: S and S
2
(with opposite orientations) and the
lateral boundary L the union of the orbits of from @S to @S
2
. Clearly, the pull-
back of
Q
to L is 0,so(5.38) implies
(5.39)
Z
S
Q
D
Z
S
2
Q
:
Applying Stokes’ theorem again, for
Q
D d Qv,wehave
Helmholtz’ theorem. For any two curves C;C
2
enclosing a vortex tube,
(5.40)
Z
C
Qv D
Z
C
2
Qv:
This common value is called the strength of the vortex tube T .
Also, note that if T is a vortex tube at t
0
D 0, then, for each t; T .t/,theimage
of T under F
t
, is a vortex tube, as a consequence of (5.35), with n D 3,since
and w D = have the same integral curves. Furthermore, (5.37) implies that the
strength of T .t/ is independent of t. This conclusion is also part of Helmholtz’
theorem.