210 4 Prologue and Epilogue: The de Sitter Universe
in R
3
and extend χ to a smooth map
˜χ :
˜
U −→ R
3
by
˜χ(φ, θ, t)=(x(φ, θ),y(φ, θ),z(φ, θ)+t)
=(sinφ cos θ, sin φ sin θ, cos φ + t).
The Jacobian of ˜χ is
⎛
⎜
⎜
⎜
⎜
⎜
⎜
⎜
⎝
∂x
∂φ
∂x
∂θ
0
∂y
∂φ
∂y
∂θ
0
∂z
∂φ
∂z
∂θ
1
⎞
⎟
⎟
⎟
⎟
⎟
⎟
⎟
⎠
and this is nonsingular at (a, 0) = (φ
0
,θ
0
, 0) ∈ R
3
.Since˜χ(a, 0) = χ(a),
the Inverse Function Theorem implies that there are open sets V and W in
R
3
with (a, 0) ∈ V ⊆
˜
U and χ(a) ∈ W ⊆ R
3
such that ˜χ|V : V → W is
a diffeomorphism. The restriction of this diffeomorphism to V ∩ ((0,π) ×
(0, 2π) ×{0}) is therefore a diffeomorphism of an open set in (0,π) ×(0, 2π)
(identified with (0,π) × (0, 2π) ×{0}) containing a onto the intersection of
the image of χ :(0,π) × (0, 2π) → R
3
with W . But this intersection is an
open set in S
2
containing χ(a) so the inverse of this last diffeomorphism is a
chart for S
2
at χ(a).
The bottom line here is this. The smooth parametrization (4.3.8)has
ma
xim
al rank at each point of (0,π) × (0, 2π) and from this alone the
Inverse Function Theorem implies that it can be smoothly inverted on an
open set about any point in (0,π) × (0, 2π), thus providing a chart in S
2
near the image of that point. This is a very powerful technique that we will
use repeatedly, but one should not get carried away. Had we not known in
advance that χ :(0,π) × (0, 2π) → R
3
is one-to-one, this would in no way
follow from what we have done with the Inverse Function Theorem, which
guarantees invertibility only near a point where the Jacobian is nonsingular.
Of course, since we do know that χ is one-to-one on (0,π)×(0, 2π) our argu-
ments show that its inverse is smooth (a map on S
2
is smooth, by definition,
if it is smooth on some open set about each point).
In order to avoid repeating the same argument over and over again we
will now prove a general result that can be applied whenever we need to
manufacture a chart. Thus, let us suppose that M is a subset of some R
m
,U
is an open set in R
n
,wheren ≤ m,and
χ : U −→ R
m