
DESIGN: COMBUSTION SYSTEMS 411
2 0 = 30 deg. In the present design, in order to meet the goal value of total pressure
loss, a sub-optimal
W/H
= 0.4 and corresponding blockage B =
D/H
= 0.314
will be utilized, where D is the lateral dimension or height of the vee-gutters and
H is the channel height or "pitch" between vee-gutters.
Equation (9.134) states that, for
W/H
---- 0.4, H must be greater than 1.042
times the product of approach velocity
U6.1
and
tBo, the
residence time at blowout
in the mixing layer at the edge of the recirculation bubble. Because U61 has been
determined from the design of the afterburner diffuser, the sole task remaining is
to use the AEDsys chemical kinetics program KINETX to determine
tBo.
Establishing inputs for KINETX requires some rather tedious calculations to
determine the composition of the mixture of core gas combustion products with
turbine cooling air and fan bypass air. The required steps are:
1) Find the composition of combustion products entering the high pressure
turbine at station 4. This can be done from stoichiometric "complete combustion"
calculations, because minor or pollutant species have a negligible effect on this
calculation, or more easily by using either of the two AEDsys programs EQL
or KINETX. Either way, the mass-specific mol numbers of major combustion
products at station 4 are found to be
no2
= 4.354 × 10 -3 lbmolsO2/lbmmixture
nN2
= 2.669 × 10 -2 lbmols N2/lbmmixture
ni42o
= 1.928 x 10 -3 lbmolsH20/lbmmixture
n¢o2
= 1.780 × 10 -3 lbmols CO2/lbmmixture
The mass-specific mole numbers at station 16 are those for air alone,
no2
= 7.098 × 10 -3 lbmols O2/lbmair
nN2
= 2.669 × 10 -2 lbmols N2/lbm air
2) From Table 9.El, the mass flow of main burner combustion products at
station 4 is 106.94 Ibm/s, and the sum of the air mass flow rates for both turbine
cooling and fan bypass is 121.69 lbm/s. The mole numbers in the combined streams
at stations 6A and 6.1 are therefore calculated to be
no2
= 5.815 × 10 -3 molsO2/lbmmixture
nN2
= 2.669 X 10 -2 molsN2/lbmmixture
ni42o
---- 9.018 x 10 -4 molsH20/lbmmixture
ncoz
= 8.326 × 10 -4 molsCO2/lbmmixture
This is the composition of the gas approaching the flameholders and being
entrained into the mixing layer at the edge of the recirculation bubble.
3) Equations (9.59) and (9.60) show that the mixing layer entrains essentially
equal amounts of cold gas and hot recirculation products, which corresponds to a
recirculation ratio
RR
= 0.5 for input to KINETX.
4) With the mass flow rate, gas composition, temperature and pressure estab-
lished at station 6.1, with recirculation ratio
RR
---- 0.5, and the afterburner fuel
mass flow rate as inputs to KINETX, there results
tso ~
8.5 × 10 -5 s.
It is now possible to determine the minimum channel height H from Eq. (9.134):
Hmin = 1.042 (U6.1
tBo)
= 1.042 (268.19) (8.5 × 10 -5) = 0.0238 ft x 12 "~ 0.3 in.