314 Chapter 14 The Lorenz System
14.4 A Model for the Lorenz Attractor
In this section we describe a geometric model for the Lorenz attractor origi-
nally proposed by Guckenheimer and Williams [20]. Tucker [46] showed that
this model does indeed correspond to the Lorenz system for certain parame-
ters. Rather than specify the vector field exactly, we give instead a qualitative
description of its flow, much as we did in Chapter 11. The specific numbers
we use are not that important; only their relative sizes matter.
We will assume that our model is symmetric under the reflection (x, y, z) →
(−x, −y, z), as is the Lorenz system. We first place an equilibrium point at the
origin in
R
3
and assume that, in the cube S given by |x|, |y|, |z|≤5, the system
is linear. Rather than use the eigenvalues λ
1
and λ
±
from the actual Lorenz
system, we simplify the computations a bit by assuming that the eigenvalues
are −1, 2, and −3, and that the system is given in the cube by
x
=−3x
y
= 2y
z
=−z.
Note that the phase portrait of this system agrees with that in Figure 14.4 and
that the relative magnitudes of the eigenvalues are the same as in the Lorenz
case.
We need to know how solutions make the transit near (0, 0, 0). Consider a
rectangle
R
1
in the plane z = 1 given by |x|≤1, 0 <y≤ < 1. As time
moves forward, all solutions that start in
R
1
eventually reach the rectangle R
2
in the plane y = 1 defined by |x|≤1, 0 <z≤ 1. Hence we have a function
h :
R
1
→ R
2
defined by following solution curves as they pass from R
1
to
R
2
. We leave it as an exercise to check that this function assumes the form
h
x
y
=
x
1
z
1
=
xy
3/2
y
1/2
.
It follows that h takes lines y = c in
R
1
to lines z = c
1/2
in R
2
. Also, since
x
1
= xz
3
1
, we have that h maps lines x = c to curves of the form x
1
= cz
3
1
.
Each of these image curves meet the xy–plane perpendicularly, as depicted in
Figure 14.7.
Mimicking the Lorenz system, we place two additional equilibria in the
plane z = 27, one at Q
−
= (−10, −20, 27) and the other at Q
+
= (10, 20, 27).
We assume that the lines given by y =±20, z = 27 form portions of the stable
lines at Q
±
, and that the other two eigenvalues at these points are complex
with positive real part.
Let denote the square |x|, |y|≤20, z = 27. We assume that the vector
field points downward in the interior of this square. Hence solutions spiral