6.1 The Drell–Yan Process 421
The expression can be further simplified by introducing coordinates
q = k
1
+k
2
and k = k
1
−k
2
, which yields
d
3
k
1
2k
0
1
d
3
k
2
2k
0
2
=
1
2
1
(q
2
0
−k
2
0
)
d
3
q d
3
k . (10)
In the center-of-mass system of the lepton pair k
1
+k
2
= 0 =q we have
Q
2
=q
2
0
, k
2
0
= 0sothatwecanwrite
1
2
d
3
q
Q
2
d
3
k =
1
2
d
3
q
Q
2
dΩ
k
|
k
|
2
d
|
k
|
=
1
2
d
3
q d
|
k
|
dΩ
k
=
1
2
d
4
q dΩ
k
. (11)
The angle dΩ
k
= dφ
k
dcosθ
k
corresponds to the angle relative to the appropri-
ately chosen axis in the lepton-pair center-of-mass system. Putting everything
together we find
dσ =
α
2
2s
1
Q
4
L
µν
W
µν
1
(2π)
4
d
4
q dΩ
k
. (12)
As seen from (8) the Drell–Yan cross section is described by the hadronic
tensor in a quite analoguos way to the hadronic tensor in the case of deep in-
elastic lepton–nucleon scattering. In the case of Drell–Yan the current product
j
ν
(0) j
µ
(x) is sandwiched not in a one-nucleon state but in the two-nucleon state
|
NN
≡
|
p
1
p
2
. Hence a similar procedure as in the case of operator product ex-
pansion is not applicable here. However, we will use a procedure a little bit more
general to derive a factorization of the short-distance part from the long-distance
part. In leading order in the strong coupling constant we insert into the hadronic
tensor the vector currents
j
µ
(x) j
ν
(0) = e
2
q
q
i
(x)γ
µ
q
j
(x)q
l
(0)γ
ν
q
k
(0)δ
ij
δ
lk
, (13)
where we have made the dependence on the color denoted by the latin indices
i, j, k, l explicit. Performing a Fierz transformation
3
on the quark fields we can
write
q
j
(x)
α
q
l
(0)
β
=−
1
4
q
l
(0)q
j
(x)
δ
αβ
−
1
4
q
l
(0)γ
q
j
(x)
γ
αβ
−
1
8
q
l
(0)σ
σ
q
j
(x)
σ
σ
αβ
−
1
4
q
l
(0)γ
5
γ
q
j
(x)
γ
γ
5
−
1
4
q
l
(0)γ
5
q
j
(x)
γ
5αβ
(14)
3
See W. Greiner and B. Müller: Gauge Theory of Weak Interactions, 3rd ed. (Springer,
Berlin, Heidelberg, New York 2000).
Example 6.5