7 The Britannica Guide to Statistics and Probability 7
62
Peter’s ruin is 0.88, only slightly less than before. However,
for x = 100 and m = 1,000, Peter’s slight advantage on each
trial becomes so important that the probability of his ulti-
mate ruin is now less than 0.02.
Generalizations of the problem of gambler’s ruin play
an important role in statistical sequential analysis, devel-
oped by the Hungarian-born American statistician
Abraham Wald in response to the demand for more effi-
cient methods of industrial quality control during World
War II. They also enter into insurance risk theory.
The following example shows that, even when it is
given that A occurs, it is important in evaluating P(B|A) to
recognize that A
c
might have occurred, and hence in prin-
ciple it must be possible also to evaluate P(B|A
c
). By lot,
two out of three prisoners—Sam, Jean, and Chris—are
chosen to be executed. There are
possible pairs of prisoners to be selected for execution, of
which two contain Sam, so the probability that Sam is
slated for execution is 2/3. Sam asks the guard which of the
others is to be executed. Because at least one must be, it
appears that the guard would give Sam no information by
answering. After hearing that Jean is to be executed, Sam
reasons that, because either he or Chris must be the other
one, the conditional probability that he will be executed is
1/2. Thus, it appears that the guard has given Sam some
information about his own fate. However, the experiment
is incompletely defined, because it is not specified how
the guard chooses whether to answer “Jean” or “Chris” in
case both are to be executed. If the guard answers “Jean”
with probability p, then the conditional probability of the