1.6. Level set equations 43
for all X, Y ∈ S
N
with X ≥ Y .HereX ≥ Y means that X − Y is a nonnegative
matrix, i.e., (X − Y )ξ, ξ ≥0 for all ξ ∈ R
N
.
This condition is a kind of monotonicity of F in X. Fortunately, many ex-
amples F
f
of level set equations fulfill this property as we see below.
Level set mean curvature flow equation. The function F
f
(p, X) defined by (1.6.6)
is degenerate elliptic. Indeed, by definition
F
f
(p, X)=−trace(R
p
Y ) − trace (R
p
(X − Y )) .
Since trace AB ≥ 0forA ≥ O, B ≥ O and R
p
≥ O, the last term is nonpositive
if X ≥ Y so (1.6.18) follows. Here O denotes the N × N zero matrix.
Level set Hamilton–Jacobi equation. The function F
f
(x, t, ·, ·) defined by (1.6.9)
is independent of X so F
f
(x, t, ·, ·) is degenerate elliptic for all x, t.Ifalevelset
equation is of first order, F
f
is always degenerate elliptic.
Anisotropic version. The function F
f
(x, t, ·, ·) defined by (1.6.11) is degenerate
elliptic if ∇
2
γ ≥ O as well as a ≥ 0andβ>0; as before we here assume that γ
is C
2
outside the origin. The idea to prove (1.6.18) is the same as the proof for
−trace (R
p
X).
Surface evolution equation by principal curvatures. The function F
f
defined by
(1.6.13) is no longer degenerate elliptic unless N = 2. We shall modify e
m
so that
F
f
is degenerate elliptic. If we consider the equation (1.5.8), F
f
in the level set
equation is of form
F
f
(p, X)=−|p| g
k
1
(p, X),...,k
N−1
(p, X), −
p
|p|
, (1.6.19)
where the k
i
’s are eigenvalues of Q
p
(X)/|p| as defined in the paragraph on the
Gaussian curvature in §1.4. There is a sufficient condition on g so that F
f
is
degenerate elliptic.
Proposition 1.6.7. For each i =1,...,N − 1,p∈ S
N−1
and (λ
1
,...,λ
i−1
,
λ
i+1
,...,λ
N−1
) ∈ R
N−2
the function λ
i
→ g(λ
1
,...,λ
N−1
; p) is nondecreasing
in R.ThenF
f
given by (1.6.19) is degenerate elliptic.
Proof. It suffices to prove that X ≥ Y implies k
i
(p, X) ≥ k
i
(p, Y )fori =
1, 2,...,N − 1. By rotation of p as in the proof of Lemma 1.6.2 we may assume
that p =(1, 0,...,0) and
Q
p
(X)=
⎛
⎜
⎝
0 ... 0
.
.
. X
0
⎞
⎟
⎠
,Q
p
(Y )=
⎛
⎜
⎝
0 ... 0
.
.
. Y
0
⎞
⎟
⎠
with X
,Y
∈ S
N−1
.Thenk
i
(p, X)equalsthei-th eigenvalue µ
i
of X
/|p| denoted
µ
i
(X
/|p|)whereµ
1
≤ µ
2
≤···≤ µ
N−1
.IfX ≥ Y , then evidently X
≥ Y
.