88
Ñîâðåìåííûé Ãóìàíèòàðíûé Óíèâåðñèòåò
Ðåøèòå ñàìîñòîÿòåëüíî ñëåäóþùèå çàäàíèÿ
Çàäàíèå 1
Îïðåäåëèòü ÌÄÑ êàòóøêè, ðàñïîëîæåííîé íà ìàãíèòîïðîâîäå, êîòîðûé
âûïîëíåí èç ëèñòîâîé ñòàëè, ñ òåì, ÷òîáû ïîëó÷èòü íà ïåðâîì ó÷àñòêå
ìàãíèòíóþ èíäóêöèþ B
1
= 2Òë. Ðàçìåðû ìàãíèòîïðîâîäà: a
1
= 60ìì; a
2
= 70ìì;
a
3
= 200ìì; a
4
= 70ìì; a
5
= 70ìì; a
6
= 60ìì; a
7
= 400ìì. Ñòûêè èìåþò
âîçäóøíûé çàçîð, ðàâíûé 0,2 ìì.
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2 Îïðåäåëåíèå
íàïðÿæåííîñòè
ìàãíèòíîãî ïîëÿ ïî
çàäàííîé çàâèñèìîñòè
ìàãíèòíîé èíäóêöèè îò
íàïðÿæåííîñòè
ìàãíèòíîãî ïîëÿ
Íàïðÿæåííîñòü ïîëÿ íà ó÷àñòêàõ 1 è 2
îïðåäåëÿåì ïî êðèâîé íàìàãíè÷èâàíèÿ.
Ñîãëàñíî êðèâîé íàìàãíè÷èâàíèÿ äëÿ
ëèñòîâîé ýëåêòðîòåõíè÷åñêîé ñòàëè
H
1
= 40 À/ñì; H
2
= 17À/ñì.
Íàïðÿæåííîñòü ïîëÿ â çàçîðàõ îïðåäåëÿåòñÿ
ïî ôîðìóëå: H
0
= B/
µ
0
= 0,8
⋅
10
6
Â;
H
3
= 0,8
⋅
10
6
⋅
Â
3
= 0,8
⋅
10
6
⋅
1,6 = 12800 À/ñì;
H
4
= 0,8
⋅
10
6
⋅
1,33 = 10640 À/ñì.
3 Îïðåäåëåíèå ÌÄÑ ñ
ïîìîùüþ çàêîíà ïîëíîãî
òîêà
Ïî çàêîíó Êèðõãîôà, ñóììà ìãíîâåííûõ
íàïðÿæåíèé íà îòäåëüíûõ ó÷àñòêàõ ðàâíà
èñêîìîé ÌÄÑ:
F = I
⋅
w = H
1
⋅
l
1
+ H
2
⋅
l
2
+ H
3
⋅
l
3
+ H
4
⋅
l
4
= 40
⋅
26 +
17
⋅
65 + + 12800
⋅
0,01 + 10640
⋅
0,01 = 2379,4
À.