301 6.2 Analysis of phase equilibrium
the invariant point, a divariant field switches from stable to metastable when it crosses a
univariant curve (see, for example, Zen, 1984). Thus, the divariant field (A, B) is stable on
one side of each of the univariant curves and metastable on the other. We can see from Fig.
6.4a that it must be stable on the side of the intersection in which the angle between the
two curves is less than 180
◦
, which is shown in the figure by the arc labeled (A, B). To see
why this must be the case let us assume that (A, B) was stable on the other side, i.e. to the
right of (A) and below (B). If this were the case then we would run into the contradiction
that between each stable curve and the metastable extension of the other one, in regions 1
and 2, (A, B) would have to be simultaneously stable and metastable. This is, essentially,
Schreinemakers’ rule: a stable divariant field always extends between the two univariant
curves that each lack one of the two phases absent from the divariant assemblage, and on
the side in which the angle between the curves is less than 180
◦
(there is a special case in
which the angle equals 180
◦
, which we discuss later). This simple rule makes it possible
to construct phase diagrams of arbitrary complexity. Remarkably, it can be stated in even
simpler terms. To see how, we note that, if (A, B) is stable to the left of (A) and above (B),
then all divariant fields that are stable to the right of (A) must contain B, and all divariant
fields that are stable below (B) must contain A. Thus, A and B must show up as reactants on
the sides of the univariant curves opposite to the (A, B) field, as shown in Fig. 6.4a – this is
of course the same conclusion that we reached in Section 6.1.1 for a one-component system.
Let us now add a third univariant curve, labeled (C). Following the same arguments as
above, we label the stable divariant fields and add the reactant phases on the opposite sides
of the univariant curves, as shown in Fig. 6.4b. It appears that we have recovered the phase
diagram from Fig. 6.3, and if this was a one component system that would be the case. In
general, however, this may be only the beginning in the construction of a phase diagram
for a system with c > 1. We can add a fourth univariant curve, labeled (D), for example
as in Fig. 6.4c. Repeating the same arguments we conclude that the identities of the stable
divariant fields and the sides on which the reactant phases plot must be as shown in this figure
(note that if we had placed the fourth curve anywhere else the diagram would be identical,
except for a rotation and some switched divariant field labels). We could keep going, but
there is little reason to do so, as Schreinemakers’method already emerges from this example.
Figure 6.4c is a thermodynamically feasible phase diagram for a system of two com-
ponents. It shows consistent relative locations of all four univariant assemblages and all
six divariant assemblages. Two of the latter, (A, D) and (B, C), extend over more than one
divariant field, and there are three divariant fields that can contain more than one equilibrium
divariant assemblage. Which is the actual equilibrium assemblage in each divariant field
depends on the bulk composition of the system, as we shall see in the following section. The
labels for the divariant assemblages, and the arcs showing their extents, are not normally
shown in phase diagrams, as there is a more compact way of showing this information
(Section 6.2.3). We can thus “clean” the diagram and obtain Fig. 6.4d, which shows how
Schreinemakers’“180
◦
rule” transforms into a rule that is much simpler to apply, regardless
of how many components the system has. This is simply a restatement of the rule that we
inferred for the case c = 1, which we now see is true in general: the metastable extension
of each univariant curve enters the only divariant field in which the phase absent along the
univariant curve appears as a reactant on the two univariant curves that bound the field.
Thus, the metastable extensions of (B) and (D) enter the same field, as B and D are reactant
phases on the two boundaries of this field. The metastable extensions of (A) and (C) enter
different divariant fields, with A and C as reactant phases on their respective boundaries.
In the divariant field bound by (B) and (D) there is no phase that appears as a reactant on