240 8 Dressing via local Riemann–Hilbert problem
corresponds to the rule that the C
+
domain is on the left when traveling along
the contour. The normalization of the RH problem (8.47) is noncanonical be-
cause, in accordance with (8.43),
Φ
+
(x, k) → Φ
(0)
+
(x),k→∞.
In general we obtain the RH problem with zeros. Suppose that all zer os
are simple. In virtue of the involution (8.46) we have an equal number N of
zeros in C
+
and C
−
. Moreover, because of the par ity property (8.40), zeros
appear in pairs as ±k
j
and ±
¯
k
l
. This means that the regularization of the RH
problem at the points ±k
j
is performed by two elementary rational multipliers,
Φ
+
Ξ
−1
j
Ξ
−1
−j
,where
Ξ
−1
j
= 11+
k
j
−
¯
k
j
k −
¯
k
j
P
j
,Ξ
−1
−j
= 11 −
k
j
−
¯
k
j
k +
¯
k
j
P
−j
,P
±j
=
|χ
±j
χ
±j
|
χ
±j
|χ
±j
,
and Φ
+
(±k
j
)|χ
±j
= 0. In virtue of the parity property, the vectors |χ
j
and |χ
−j
are interrelated, |χ
−j
= σ
3
|χ
j
, and th erefore P
−j
= σ
3
P
j
σ
3
.
After the complete regularization, we once again arrive at the factorizable
representation of Φ
±
,
Φ
±
= φ
±
Γ, Γ = Ξ
N
Ξ
−N
···Ξ
1
Ξ
−1
, (8.48)
where φ
±
solve the regular RH problem
φ
−1
−
φ
+
= ΓEG
0
E
−1
Γ
−1
. (8.49)
Comparing the asymptotic expansion
Γ (x, k)=
11+k
−1
Γ
(1)
(x)+O(k
−2
)
with that for Φ
+
(8.43), we obtain from (8.48)
Φ
(0)
+
= φ
+
,Φ
(1)
+
= Φ
(0)
+
Γ
(1)
.
Hence, we can take the leading-order term Φ
(0)
+
(x) of the asymptotic expansion
(8.43) as a k-independent solution of the regular RH problem. In turn, the
reconstruction formula (8.45) now takes the form
Q =
2
α
Φ
(0)
+
Γ
(1)
!
Φ
(0)
+
"
−1
. (8.50)
Note that because the RH problem for the NLS equation allows the standard
normalization, we took a trivial solution (φ
+
= 11) of the regular RH problem
(8.19). It should be stressed once again that a choice of a k-independent
solution of the regular RH problem is valid for solitons only. If we want to
account for the nonsolitonic part of a solution, we should consider a nontrivial
solution of the regular RH problem. As a rule, the r egular RH problem do es