491
The requirement for Theorems 2.4 and 2.5 is
3A\
2
- 3BXa + Ca
2
+
V>i(A,
a) = 0,
near
(A,
a) = (0,0). Here we find that
condition (6)
<=>
9B
2
- Y1AC < 0,
condition (7) <S=> 9B
2
- Y1AC > 0.
This implies that conditions (6) and (7) determine the sign of the discriminant for
the quadratic function 3A\
2
—
3B\a + Ca
2
. Prom this observation, the conclusions in
Theorems 2.4 and 2.5 follow under the analyticity of g.
The extension to the case g without the analyticity assumption is due to a comparison
argument using the super- and sub-solution method as follows. Senn proved in [8] that if
J
D
mdx = 0, then the principal eigenvalue Hi{\) of (3) is negative for any
A
> 0. Denote
by ipi(X) the principal positive eigenfunction of (3). We can easily see under (2) that for
every A > 0 a function
E<pi(\)
is a sub-solution of (1) for any e > 0 small enough.
For any g satisfying (5) and (6) without the analyticity assumption, there exists
<5i
> 0
close to g'"(0) such that
t<™«-/
to
K.)*>
55
$g
p=
.
Let gi (t) = Sit
3
/6. Then there exists ri > 0 such that
b(x)
gi
(t)<b(x)g(t), te[0,n}. (9)
One sees that gi fulfills (5) and (6) and is analytic at t = 0, so that there is no positive
solution u of (1) with g = g
x
for any A > 0 and
||M||C2+«(C)
both small enough in the
previous argument. By the well-known bootstrap argument, the same situation holds for
A > 0 and u
G
C(D) both small enough.
Now we assume to the contrary that the origin (A,u) = (0,0) is a bifurcation point
to the right for the original problem (1) and, without loss of generality, there may exist
positive solutions u^ of (1) such that
||WA||C(D)
—» 0 as A J. 0, so that it follows that
II
U
A|IC(D)
< TI for 0 <
A
< A* with some
A*
> 0. This implies that ux is a super-solution
of (1) with g = gi for any 0 < A < A*, by virtue of (9). We recall the existence of such
sub-solutions of (1) with g = g\ which are sufficiently small. Then the super- and sub-
solution method allows us to obtain that for any A > 0 small the existence of a positive
solution v\ of (1) with g = g\ such that 0 < v\ < u\ on D. This proves that
||«A||C(5)
~~
y
0
as
A
J. 0, which is a contradiction. The proof of Theorem 2.4 is complete. •
Now we end the proof of Theorem 2.5 in an analogous way. Indeed, it suffices to note
that for any g satisfying (5) and (7) without analyticity, we can take a constant
&
z
> 0
such that
r 3n
2
IDI
2
5
"'(0)<5
2
and / b{x)da< * ' .