V.7. Symplectic manifolds 207
(i) ! is nondegenerate,
(ii) ! is closed, i.e., d! D 0.
The differential form ! is called nondegenerate, if in every point x 2 M the
2-form !.x/ on the tangent space T
x
M is nondegenerate, i.e., !.x/.u; v/ D 0 for
all v 2 T
x
M implies u D 0. Equivalently, the map u 7! !.x/.u; / from the
tangent space T
x
M onto its dual space .T
x
M/
is a linear isomorphism.
By definition, every tangent space
T
x
M; !.x/
is a symplectic vector space. A
first example for a symplectic manifold is the pair .U; !
0
/ in which U R
2n
is an
open set and !
0
is the standard symplectic structure on R
2n
. Actually this is what
every symplectic manifold looks like locally, according to the following theorem
of Darboux.
Theorem V.22 (Darboux). If ! is a nondegenerate 2-form on the manifold M of
dimension dim M D 2n, then d! D 0 if and only if there exists around every point
p 2 M a chart .U; '/ satisfying '.p/ D 0 2 R
2n
and
!j
U
D '
!
0
;
where !
0
D
P
n
j D1
dy
j
^dx
j
is the constant symplectic standard structure on R
2n
.
Definition. These special coordinates are called symplectic coordinates or Darboux
coordinates. A chart .U; '/ on which !j
U
D '
!
0
is called a Darboux chart.
In view of Darboux’s theorem we do not have to look for local invariants!
Corollary V.23. Two symplectic manifolds of the same dimension have locally the
same normal form, namely .R
2n
;!
0
/. They are therefore locally indistinguish-
able: Symplectic manifolds do not possess local symplectic invariants except the
dimension!
The situation is completely different from Riemannian manifolds. Two Rie-
mannian metrics are in general not locally isometric. The Gauss curvature is an
example of a local invariant.
Proof of Theorem V.22 [Deformation trick by R. Thom and J. Moser, Cartan’s
formula, Poincaré lemma]. We first assume that the nondegenerate 2-form is closed
so that d! D 0. In local coordinates ! D !.z/ is a nondegenerate 2-form on R
2n
,
which depends on the point z 2 R
2n
. By a translation we may assume that the
point p in M corresponds to z D 0, and by a linear transformation of R
2n
we can
achieve, in view of Proposition V.2 , that in the point z D 0 the 2-form is already in
normal form,
!.0/ D !
0
D
n
X
j D1
dy
j
^ dx
j
: