22.7 Problems 589
In order to find the pressure tendency we integrate the continuity equation, i.e.
the last equation of (22.58), between θ and θ →∞and obtain with the help of the
Leibniz rule
∂p
∂t
= m
2
0
∂
∂x
∞
θ
v
1
∂p
∂θ
dθ
+
∂
∂y
∞
θ
v
2
∂p
∂θ
dθ
(22.61)
For adiabatic flow the θ system has the decisive advantage that the vertical
velocity vanishes everywhere so that we are dealing with two-dimensional motion.
As soon as nonadiabatic effects must be taken into account this advantage is lost,
so the θ system is not used for routine numerical investigations. Therefore, we will
omit a detailed discussion of the integration cycle.
Finally, we would like to remark that other generalized vertical coordinates might
be used, such as the density of the air. The theory for this system has been worked
out, but it has not yet found many important applications.
22.7 Problems
22.1: By a direct transformation obtain the first equation of (22.11) from the first
equation of (22.10). Compare your result with equation (20.48).
22.2: Show that equations (22.20) and (22.21) follow from (22.15) and (22.16).
22.3: Balloons drifting on surfaces of constant density could be used to collect
global atmospheric data. To utilize these data, we need a predictive system using
ρ as a vertical coordinate.
(a) Introduce the Montgomery potential for the ρ system N = R
0
T + φ to find
the horizontal equation of motion in terms of the covariant velocity components.
Obtain the hydrostatic equation. State the individual derivative d/dt for this system.
(b) Find the continuity equation.
(c) Formulate the upper and lower boundary conditions for the ρ system.
(d) Find an expression for the pressure tendency ∂p/∂t.
22.4: Consider an idealized atmosphere consisting of an incompressible friction-
less fluid with a free surface z
H
. Assuming that v
h
is independent of height, find a
prognostic equation for the free surface.
22.5: Consider the equation of motion for a frictionless fluid in Cartesian coordi-
nates (m
0
= 1) in simplified form, i.e.
dv
h
dt
q
i
=−
1
ρ
∇
h,ξ
p − f k × v
h
−∇
h,ξ
φ