Bellman’s Principle of Optimality and Its Generalizations
151
First, if a relation g ⊆ W
2
is a partial ordering, g must be strongly antisymmetric.
Suppose that this statement is not true. That is, the relation g
⊆ W
2
is a partial
ordering but not a strongly antisymmetric relation. Hence, there exist
w
1
,
w
2
∈ W
such that w
1
≠ w
2
, and natural numbers m, n ∈ such that and
From the transitivity of
g
, it follows that
and w
1
≠ w
2
. This last condition contradicts the antisymmetry of g. Second, the
following example shows that a strongly antisymmetric relation g
⊆ W
2
may not
be a partial ordering relation.
Example 7.7.1. Let W = and for any a, b
∈ W, (
a
, b) ∈ g ⊆ W
2
, iff b + 1 >
a > b. It can be shown that (
a
,b
)
∈
g
m
, for
m
∈
iff b + m ≥ b + 1 > a > b ;
and that (
b
,a
)
∈
g
n
, for n ∈ iff a + m ≥ a + 1 > b > a. Therefore, g is strongly
antisymmetric.
However, it is not a partial ordering relation on W, since the
transitivity relation is not satisfied.
Theorem 7.7.1 [Qin (1991)]. If a set W is finite, then a binary relation g
⊆ W
2
is strictly strongly antisymmetric iff the relation g is strongly antisymmetric.
Proof: Necessity. Suppose that g
⊆ W
2
is strictly strongly antisymmetric but
not strongly antisymmetric. From the definition of strong antisymmetry it follows
that there exist w
1
, w
2
∈ W and m
,
n
∈
such that
and
Thus, there exist elements w
1i
, i = 1, . . . , m – 1, and w
2
j
,
j
= 1, 2 , . . . ,
n
– 1, such that
and
That is, there exists a finite sequence
such that
x
i
≠ x
i +1
, for i = 1, 2 , . . . , m + n–1 and (x
i
,x
i +1
) ∈ g, for i =1, 2, . . . , m + n–1
Now an infinite sequence can be defined as follows:
and
It is easy to observe that y
i
≠ y
i +1
and (y
i
,y
i +1
) ∈ g for each i ∈
which
contradicts the assumption that g is strictly strongly antisymmetric.
Sufficiency. Suppose W is finite and g
⊆ W
2
is strongly antisymmetric. As-
sume that g
⊆ W
2
is not strictly strongly antisymmetric. There then exists an
infinite sequence
such that y
i -1
≠ y
i
and (y
i –1
, y
i
)
∈
g
for each
i
∈