
502 SECTION 8 Solid-State Devices
connected to the same polarity as the anode if it is
to turn the anode-cathode section of the SCR on.
Once the gate has turned the SCR on, it will remain
turned on until the current owing through the
anode-cathode drops to a low enough level to per-
mit the device to turn off. The amount of current
required to keep the SCR turned on is called the
holding current, Figure 54–4. Assume resis-
tor R1 has been adjusted for its highest value and
resistor R2 has been adjusted to its lowest or 0
value. When switch S1 is closed, no current will
ow through the anode-cathode section of the
SCR because resistor R1 prevents enough current
owing through the gate-cathode section of the
SCR to trigger the device. If resistor R1 is slowly
decreased in value, current ow through the gate-
cathode will slowly increase. When the gate cur-
rent reaches a certain level, assume 5 mA for this
SCR, the SCR will re or turn on. When the SCR
res, current will ow through the anode-cathode
section and the voltage drop across the device
becomes about 1 volt. Once the SCR has turned
on, the gate has no more control over the device
and could be disconnected from the anode without
having any effect on the circuit. When the SCR
res, the anode-cathode becomes a short circuit for
all practical purposes and current ow is limited by
resistor R3. Now assume that resistor R2 is slowly
increased in value. When the resistance of R2 is
slowly increased, the current ow through the
anode-cathode will slowly decrease. Assume that
when the current ow through the anode-cathode
drops to 100 mA, the device suddenly turns off
and the current ow drops to 0. This SCR requires
5 mA of gate current to turn it on, and has a hold-
ing current value of 100 mA.
appear across the anode and cathode. Although
the SCR has a voltage drop of 200 volts, there is no
current ow in the circuit. The SCR does not have
to dissipate any power in this condition (200 volts ⫻
0 amps ⫽ 0 watts). When the push button is pressed,
the SCR will turn on. When the SCR turns on, it will
have a voltage drop across its anode and cathode
of about 1 volt. The load resistor limits the circuit
current to 2 amps (200 volts/100 ohms ⫽ 2 amps).
Because the SCR now has a voltage drop of 1 volt
and 2 amps of current is owing through it, it must
now dissipate 2 watts of heat (1 volt ⫻ 2 amps ⫽
2 watts). Notice that the SCR is dissipating only
2 watts of power, but is controlling 200 watts.
THE SCR IN A DC CIRCUIT
When an SCR is connected in a DC circuit as shown
in Figure 54–3, the gate will turn the SCR on
but will not turn the SCR off. The gate must be
PN NP
Figure 54–1
PNPN junction. (Source: Delmar/Cengage Learning)
ANODE+–CATHODE
GATE
Figure 54–2
Schematic symbol of an SCR. (Source: Delmar/Cengage Learning)
200 VOLTS DC
LOAD 100 OHMS
Figure 54–3
Gate turns SCR on. (Source: Delmar/
Cengage Learning)