
//FS2/CUP/3-PAGINATION/SDE/2-PROOFS/3B2/9780521873628C08.3D
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Earth-based measurements of tides do not
give h or k directly, but only combinations of
them. The marine tide responds to the total
potential of the deformed Earth, but is observed
relative to the deformed solid Earth. Similarly,
tidal gravity is observed at sites which are them-
selves displaced by the tides. There is also a prob-
lem that, at the semi-diurnal and diurnal
periods, the marine tides are far from equili-
brium. There are longer-period components of
the tides, that are presumed to be close to equi-
librium, but they are small and are less easily
observed. Satellite measurements, using a fur-
ther development of the analysis in Chapter 9,
give individual Love numbers directly and it is
the satellite values that are the most precise, as
well as the most reliable.
8.3 Tidal friction
The response of the Earth to the lunar tidal
potential, W
2
, is a deformation causing an addi-
tional potential k
2
W
2
. If the tides were perfectly
linear and lossless, this would be an exact expres-
sion, but the tidal bulge is slightly delayed by
turbulent drag in the sea and by anelasticity of
the solid part of the Earth. Also the non-linear
ocean response introduces higher harmonics.
We can represent the delay as a departure of
the prolate tidal elongation from alignment
with the Earth–Moon axis by a small angle, .
As discussed below, the measured value of is
about 2.98, so that the global high tide occurs at
points that were directly in line with the Moon
(2.9/360) 24.84 hours ¼12 minutes ago. Thus,
the tidal potential at the Earth’s surface, due to
the tidal deformation of the Earth itself, is
W
E;a
¼
k
2
Gma
2
R
3
3
2
cos
2
w ðÞ
1
2
; (8:17)
where m is the mass of the Moon, R is its distance,
a is the Earth’s radius and w is here the angle
between the Earth–Moon axis and the radius to a
surface point in the orbital plane. At any more
remote point (r, w), that is at r > a, the potential,
W
E
,
r
, is reduced by the factor (a/r)
3
because the
geometrical form of Eq. (8.17) is a second-degree
zonal harmonic, similar to the second term of
Eq. (6.15), and diminishes with distance r as r
3
.
W
E;r
¼
k
2
Gma
5
R
3
r
3
3
2
cos
2
w ðÞ
1
2
: (8:18)
Thus, there is a tidal torque exerted on any mass
m
at this point,
L
T
¼m
@W
E;r
@ w ðÞ
¼
3k
2
Gmm
a
5
R
3
r
3
cos w ðÞsin w ðÞ: (8:19)
The observation of this torque by means of close
satellites allows k
2
and to be determined (e.g.
Christodoulidis et al., 1988).
Now consider the tidal torque exerted on the
Moon, for which m
¼m, r ¼R and w ¼0,
L
T;Moon
¼
3k
2
Gm
2
a
5
R
6
cos sin
3k
2
Gm
2
a
5
R
6
:
(8:20)
This torque acts in the direction that would
reduce , that is, it tries to make the Moon
‘catch up’ with the tidal bulge of the Earth. The
bulge appears to the Moon to be ahead of its own
orbital motion, although with respect to the
Earth, which is rotating faster, the bulge is seen
to be delayed. Hence, the effect of the lag of the
bulge, caused by frictional losses of the tides in
the Earth, is to apply an accelerating torque to
the orbital motion of the Moon. The equal torque
exerted by the Moon on the bulge tends to pull
the bulge into line with the Moon and so acts as a
brake on the Earth’s rotation (Fig. 8.4). Angular
momentum is conserved. The angular momen-
tum gained by the Moon is the same as that lost
by the Earth because the torques are equal.
However, energy is lost from the motion. The
Moon’s orbit gains energy (kinetic plus potential)
at a rate !
L
L
T,Moon
and the Earth’s rotation loses
energy at a greater rate !L
T,Moon
. The net rate of
loss of energy is (! !
L
)L
T,Moon
¼3.06 10
12
W,
that is, the torque times the angular speed of
the tide relative to the Earth. Adding the energy
dissipation by the solar tide we have a total of
3.7 10
12
W.
Observed values of the tidal parameters in
Eq. (8.20) are k
2
¼0.245, ¼2.898, giving a value
106 TIDES AND THE EVOLUTION OF THE LUNAR ORBIT