APPENDIXES A.7
L = channel length (m)
P = total power expenditure or rate or energy dissipation (W)
Q = DBV = total discharge (m
3
/s)
q = Q/B = discharge per unit channel width (m
3
/s m = m
2
/s)
S = slope of energy grade line (dimensionless)
V = velocity (m/s)
γ = gamma, the unit weight of fluid (N/m
3
)
τ = γDS = bed shear stress
Units are given in brackets [W = watts].
The rate of energy dissipation or the power of expenditure by flowing water is given
by:
P = γ Q ∆E [W] (J.1)
Thus, the total power expended by 1 m
3
/s of water dropping through a 0.5 m vertical
fall may be computed as:
P = (9810 N/m
3
)(1 m
3
/s)(0.5 m) 4905 W
For flow along a channel let ∆E = SL and Q = DBV so that:
P = γQSL = γ(DBV)(SL) [W] (J.2)
Although in streams the bed slope or the water surface slope can be used to approximate
the energy slope, this approximation may lead to unacceptable error when varying
flow is being analyzed.
The rate of energy dissipation per unit of channel length may be computed by re-
arranging Eq. (J.2)
P / L = γQS = [W/m] (J.3)
The rate of energy dissipation may be computed per unit area of channel bed by
rearranging Eq. (J.2) and substituting
τ =
γDS
P/(BL) = γDSV = τV [W/m
2
] (J.4)
The rate of energy dissipation per unit weight of water is termed unit stream power and
may also be obtained by rearranging Eq. (J.2)
P / (γDBL) = VS [m/s] (J.5)