
Systems in Nuclear Medicine 355
Example 7.2 Biomechanical Model of Pulmonary Inhalation/Exhalation
Inhalation and exhalation can be described by a biomechanical system
illustrated in Figure 7.8.
In a relaxed state, without any air flow, the pressure inside the lungs is equal
to the atmospheric pressure, P
B
. During inhalation, the respiratory muscles—
the diaphragm and the thoracic muscles—contract and lower pleural pressure
P
pl
(t) around the lungs inside the chest.
Due to their elasticity (described by the compliance C, the inverse of plas-
ticity), the lungs expand as the transmural pressure decreases; and as a
consequence, the pressure inside the lungs P
L
(t) momentarily decreases. The
pressure in the fluidic resistance R
f
of the respiratory tract falls, resulting in a
flow of air to the inside of the lungs. As long as the muscles contract increas-
ingly strongly, this process is repeated and inhalation continues. At the end
of inhalation, the abdomen and chest muscles contract and force P
pl
(t) to
exceed P
B
(atmospheric pressure), thus expelling the air from the lungs. In
resting respiration, the exhalation muscles do not need to contract, because
the relaxation of the inhalation muscles alone is enough to make P
pl
(t) greater
than P
B
.
This biomechanical process can be mathematically described based on the
physical properties of the physiological structures involved. It is a mixed
fluidic-mechanical system.
Theair flow depends on the pressure difference though thefluidic resistance
R
f
and on the resistance itself. If I(t) represents the air flow rate of inhalation
or exhalation, we will have Equation 7.38.
I(t) =
P
B
−P
L
(t)
R
f
, or, P
B
−P
L
(t) = I(t)R
f
. (7.38)
If V(t) is the volume of the lungs during the time interval Δt, the volume
variation will be Equation 7.39, assuming I(t) to be constant during Δt, then
Equation 7.39,
V
L
(t +Δt) − V
L
(t) = I(t) Δt ⇒
V
L
(t +Δt) − V
L
(t)
Δ t
= I(t) ⇒ I(t) =
˙
V
L
(t),
(7.39)
Substituting Equation 7.39 in Equation 7.38, we get Equation 7.40.
P
B
−P
L
(t) =
˙
V
L
(t)R
f
. (7.40)
The compliance of the lungs C
L
is defined by the relation between the
volume of the lungs and the transmural pressure. Mathematically, it is
Equation 7.41.
C
L
=
V
L
(t)
P
L
−P
pl
(t)
. (7.41)