
January 9, 2009 10:21 World Scientific Book - 9.75in x 6.5in ws-bo ok975x65˙n˙2nd˙Ed
Electromagnetic Interaction of Radiation in Matter 119
effects involving energy transfers small with respect to energy losses by collision
or by radiation. They occur at very reduced scale (i.e., for distances of approach
smaller than the atomic radius) or at very large scale, so that the medium po-
larization has to be taken into account. In this section, we describe the effect of
the nuclear Coulomb elastic interaction resulting in the so-called multiple scattering
and relaxation effects of polarized media via the emission of
˘
Cerenkov radiation and
transition radiation.
2.2.1 The Multiple Coulomb Scattering
When a charged particle passes in the neighborhood of a nucleus, the most impor-
tant effect is the deflection of its trajectory. Associated with the deflection, there are
photons emitted whose overall energy is usually very small with respect to that of
the incoming particle. Cases with large energy emissions are limited statistically. To
a first approximation, we treat elastic Coulomb scatterings. In an elastic scattering,
the total-momentum conservation requires that the incident particle of charge ze
acquires an equal, but opposite transverse momentum with respect to the one ac-
quired [see Eq. (2.7)] by the recoil nucleus of charge Ze. This transferred momentum
is usually very small in comparison with the incoming particle momentum p. Thus,
the incoming particle is scattered at an angle θ given approximately by the ratio of
the transverse momentum to the total momentum p, i.e.,
θ ≈
2Zze
2
bv
p
−1
=
2Zze
2
bvp
, (2.122)
where v is the particle velocity. From Eq. (2.122), the absolute value of the deflection
dθ at an angle θ is related to the impact parameter variation db at b by:
dθ =
2Zze
2
b
2
vp
db
=
θ
2
vp
2Zze
2
db. (2.123)
The probability of collision dP
el
of a particle traversing
§
a thickness dx with an
impact parameter between b and b + db is
dP
el
= 2 n
A
πb db dx
= 2
Nρπ
A
b db dx,
and, by introducing Eq. (2.122) for b and Eq. (2.123) for db, dP
el
becomes
dP
el
= 2
Nρπ
A
·µ
2Zze
2
vp
¶
θ
−1
¸
"
µ
θ
2
vp
2Zze
2
¶
−1
dθ
#
dx
= 2
Nρπ
A
µ
2Zze
2
vp
¶
2
dθ
θ
3
dx,
§
In the traversed material, n
A
is the number of atoms with atomic weight A per cm
3
[Eq. (1.39)].