Caustic Structure of Wavefield in Random Media 367
where we introduced the natural scale of length L
f
(x) =
√
x/k in plane x = const; this
scale is independent of medium parameters and is equal in size to the first Fresnel zone
that determines the size of the light–shade region in the problem on wave diffraction
on the edge of an opaque screen (see, e.g., [33, 34]).
The first approximation of Rytov’s SPM for amplitude fluctuations is valid in the
general case under the condition
σ
2
0
(x) 1.
The region, where this inequality is satisfied, is called the weak fluctuations region.
In the region, where σ
2
0
(x) ≥ 1 (this region is called the strong fluctuations region),
the linearization fails, and we must study the nonlinear system of equations (13.24),
(13.25).
As concerns the fluctuations of angle of wave arrival at the observation point
α(x, R) =
1
k
|∇
R
S(x, R)|, they are adequately described by the first approximation
of Rytov’s SPM even for large values of parameter σ
0
(x).
Note that the approximation of the delta-correlated random field ε(x, R) in the con-
text of Eq. (13.1) only slightly restricts amplitude fluctuations; as a consequence, the
above equations for moments of field u(x, R) appear to be valid even in the region
of strong amplitude fluctuations. The analysis of statistical characteristics in this case
will be given later.
13.3 Method of Path Integral
Here, we consider statistical description of characteristics of the wavefield in random
medium on the basis of problem solution in the functional form (i.e., in the form of
the path integral).
As earlier, we will describe wave propagation in inhomogeneous medium start-
ing from parabolic equation (13.1), page 355, whose solution can be represented in
the operator form or in the form of path integral by using the method suggested by
E. Fradkin in the quantum field theory [74–76].
To obtain such a representation, we replace Eq. (13.1) with a more complicated one
with an arbitrary deterministic vector function v(x); namely, we consider the equation
∂
∂x
8(x, R) =
i
2k
1
R
8(x, R) + i
k
2
ε(x, R)8(x, R) + v(x)∇
R
8(x, R),
8(0, R) = u
0
(R).
(13.45)
The solution to the original parabolic equation (13.1) is then obtained by the formula
u(x, R) = 8(x, R)|
v(x)=0
. (13.46)