10.
Proof of Theorem
1.2
213
and in particular
v(O,
-c}
= lho. Since v is HOlder continuous, the set
{x
I
u(x,-c}
<2ho}
is non-empty and contains a ball about the origin. We claim that in particular it
contains the ball
B
2
f/'
where
(277}P
=
(~)
2-
p
•
If
not, there would exist some x E
B2f/
such that v(x,
-c}
=
2ho.
It follows that
the ball
Ix
-
xlP
< [v(x, _c}]p-2 =
(2'77}P
covers the origin, and (10.6) for x=O gives
2 1
- =
v(x,-c)
$
-.
~o ~o
The contradiction proves the lemma.
To prove the estimate above in (10.3), we combine the quantitative bound
(10.5) with Proposition 4.1. This gives
We return
to
the
original coordinates and write the estimate above in (10.3) as
u(x,t
o
}
$
Cu(x.,t.},
'v'lx
-
xol
<
77R,
XO
==
x
•.
Since,
by
Corollary 1.1, u
(x.,
t.)
$~u(xo,
to}
the left estimate in (10.1) is proved.
The estimate below in (10.3) reads
u(x,
to}
~
~ou
(x.,
t.)
,
On
the other hand the estimate above in (10.3) for x =
x.
gives u(x
o
,
to}
$
Cu
(x.,
t.).
Combining these last two estimates proves the bound above in (10.1)
and the proposition follows.
1D-(i).
Proof
of
Theorem
1.2
Fix (x
o
,
to)
E
fh
and p >
O.
Let
77
be
the
constant claimed by Lemma 10.1
and let
~
be
the
constant
of
the Harnack estimate (1.3). Set
~
r =
~
I'
p/T},
and construct the cylinder