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214 CHAPTER 2
Linear Functions and Models
Set y-values equal
Subtract 5t, add 2400
Divide by 3
So the cyclists meet when Jordanna has cycled for 800 seconds, or
minutes. Since Petra left 5 minutes later, she travels
minutes to catch up with Jordanna.
To find how far the cyclists have traveled when they meet, we replace t by
800 in either one of the equations.
Replace t by 800 in Jordanna’s equation
So they have cycled 4000 meters when they meet.
NOW TRY EXERCISE 33
y = 518002= 4000
13.3 - 5 = 8.3
800>60 L 13.3
t = 800
3 t = 2400
8 t - 2400 = 5t
2
Modeling Supply and Demand
Economists model supply and demand for a commodity using linear functions. For
example, for a certain commodity we might have
where p is the price of the commodity. In the supply equation, y (the amount produced)
increases as the price increases because if the price is high, more suppliers will manu-
facture the commodity. The demand equation indicates that y (the amount sold)de-
creases as the price increases. The equilibrium point is the point of intersection of the
graphs of the supply and demand equations; at that point, the amount produced equals
the amount sold.
Demand equation:
y =-3p + 15
Supply equation: y = 8p - 10
example
4
Supply and Demand for Wheat
An economist models the market for wheat by the following equations.
Here, p is the price per bushel (in dollars), and y is the number of bushels produced
and sold (in millions).
(a) Use the model for supply to determine at what point the price is so low that no
wheat is produced.
(b) Use the model for demand to determine at what point the price is so high that
no wheat is sold.
(c) Find the equilibrium price and the quantities produced and sold at equilibrium.
Solution
(a) If no wheat is produced, then y 0 in the supply equation.
Set y 0 in the supply equation
Solve for p
p L 2.75
0 = 3.82p - 10.51
Demand:y =-0.99p + 25.34
Supply:y = 3.82p - 10.51
SECTION 2.7
Linear Equations: Where Lines Meet 215
So at the low price of $2.75 per bushel, the production of the wheat halts
completely.
(b) If no wheat is sold, then in the demand equation.
Set y 0 in the demand equation
Solve for p
So at the high price of $25.60 per bushel, no wheat is sold.
(c) To find the equilibrium point, we set the supply and demand equations equal
to each other and solve.
Set functions equal
Add 10.51
Add 0.99p
Divide by 4.81
So the equilibrium price is $7.45. Evaluating the supply equation for ,
we get
So for the equilibrium price of $7.45 per bushel, about 18 million bushels of
wheat are produced and sold.
NOW TRY EXERCISE 35
y = 3.8217.452- 10.51 L 17.95
p = 7.45
p L 7.45
4.81p = 35.85
3.82p =-0.99p + 35.85
3.82p - 10.51 =-0.99p + 25.34
p L 25.60
0 =-0.99p + 25.34
y = 0
2.7 Exercises
Fundamentals
1. (a) To find where the graphs of the functions and
intersect, we solve for x in the equation
_______ _______
(b) To find where the graphs of the functions and intersect,
we solve for x in the equation
_______ _______. So the graphs of these
functions intersect when x
_______. Therefore the graphs intersect at the point
(____, ____).
2. (a) The point where the graphs of supply and demand equations intersect is called the
______________ point.
(b) The supply of a product is given by the equation , and the demand is
given by the equation , where p is the price of the product. To find
the price for which supply is equal to demand, we solve for p in the equation
______________ ______________.
Think About It
3. Muna’s and Michael’s distances from home are modeled by the following equations.
Explain why Michael will never catch up with Muna.
Michael’s equation:
y = 2 + 3t
Muna’s equation:
y = 4 + 3t
y = m
2
p + b
2
y = m
1
p + b
1
=
y = 3x - 10y = 2x + 7
=
y = m
2
x + b
2
y = m
1
x + b
1
CONCEPTS
216 CHAPTER 2
Linear Functions and Models
SKILLS
1
_1
2
_2
3
_3
1_1 2345
0
y
x
2
2
y
x
0
4. Udit is walking from school to his home 5 miles away, starting at time t 0. Udit walks
slowly at a speed of 2 miles per hour. If the time t is measured in hours, then
.
.
5–6 A graph of two lines is given.
(a) Use the graph to estimate the coordinates of the point of intersection.
(b) Find an equation for each line.
(c) Use the equations from part (b) to find the coordinates of the point of intersection.
Compare with your answer to part (a).
5. 6.
Udit’s distance from home at time t is y =
+
t
Udit’s distance from school at time t is y =
+
t
7–10
Linear functions f and are given.
(a) Graph f and , and use the graphs to estimate the value of x where the graphs
intersect.
(b) Find algebraically the value of x where the graphs of f and intersect.
7. ; 8. ;
9. ; 10. ;
11–16
Find the value of x for which the graphs of the two linear equations intersect.
11. ; y x 12. ; y 7 x
13. ; 14. ;
15. ; 16. ;
17–22
Find the point at which the graphs of the two linear equations intersect.
17. ; 18. ;
19. ; 20. ;
21. ; 22. ;
23–24
Two linear functions are described verbally. Find equations for the functions, and
find the point at which the graphs of the two functions intersect.
23. The graph of the linear function f has slope and y-intercept 5; the graph of the linear
function has slope 5 and y-intercept 2.
24. The graph of the linear function f has x-intercept 4 and y-intercept ; the graph of the
linear function has x-intercept and y-intercept 10.
25–26
Equations for supply and demand are given. Find the price (in dollars) and the
amount of the commodity produced and sold at equilibrium.
- 2g
- 1
g
2
3
y = 6.6 + 0.6xy = 9 + xy =
3
10
x - 12y = 6 -
3
2
x
y = 40 - 3xy =
1
3
xy = 5x - 2y =
7
2
-
1
2
x
y = 9x + 6y =
4
3
x -
28
3
y =
4
3
x + 3y = 2 + x
y =
2
3
x +
1
3
y = 7 - xy = 2x - 3y =
5
3
-
1
3
x
y =-4 -
1
2
xy =-
3
2
xy =
2
3
x - 3y = 3 -
4
3
x
y x 3y = 4 - x
g1x 2=-3x + 6f 1x 2= 2x - 4g1x 2=-2x + 2f 1x2= x - 4
g1x 2=-x - 1f 1x2= x + 3g1x 2=-2x + 3f 1x 2= 2x - 5
g
g
g
SECTION 2.7
Linear Equations: Where Lines Meet 217
25. 26.
27. Cell Phone Plan Comparison Dietmar is in the process of choosing a cell phone and
a cell phone plan. The first plan charges 20¢ per minute plus a monthly fee of $10, and
the second plan offers unlimited minutes for a monthly fee of $100.
(a) Find a linear function f that models the monthly cost of the first plan in terms
of the number x of minutes used.
(b) Find a linear function that models the monthly cost of the second plan in
terms of the number x of minutes used.
(c) Determine the number of minutes for which the two plans have the same
monthly cost.
28. Solar Power Lina is considering installing solar panels on her house. Solar
Advantage offers to install solar panels that generate 320 kWh of electricity per month
for an installation fee of $15,000. She uses 350 kWh of electricity per month, and her
local utility company charges 20¢ per kWh.
(a) If Lina gets all her electrical power from the local utility company, find a linear
function U that models the cost of electricity for x months of service.
(b) If Lina has Solar Advantage install solar panels on her roof that generate 320 kWh
of power per month, find a linear function S that models the cost S(x) of electricity
for x months of service.
(c) Determine the number of months it would take to reach the break-even point
for installation of Solar Advantage’s solar panels, that is, determine when .
29. Renting Versus Buying a Photocopier A certain office can purchase a photocopier
for $5800 with a maintenance fee of $25 a month. On the other hand, they can rent the
photocopier for $95 a month (including maintenance). If they purchase the photocopier,
each copy would cost 3¢; if they rent, the cost is 6¢ per copy. The office manager
estimates that they make 8000 copies a month.
(a) Find a linear function C that models the cost of purchasing and using the
copier for x months.
(b) Find a linear function S that models the cost of renting and using the copier
for x months.
(c) Make a table of the cost of each method for 1 year to 3 years of use, in 6-month
increments.
(d) For how many months of use would the cost be the same for each method?
30. Cost and Revenue A tire company determines that to manufacture a certain type of
tire, it costs $8000 to set up the production process. Each tire that is produced costs $22
in material and labor. The company sells this tire to wholesale distributors for $49 each.
(a) Find a linear function C that models the total cost of producing x tires.
(b) Find a linear function R that models the revenue from selling x tires.
(c) Find a linear function P that models the profit from selling x tires.
[Note: .]
(d) How many tires must the company sell to break even (that is, when does revenue
equal cost)?
31. Car Rental A businessman intends to rent a car for a 3-day business trip. The rental is
$35 a day and 15¢ per mile (Plan 1) or $90 a day with unlimited mileage (Plan 2). He is not
sure how many miles he will drive but estimates that it will be between 1000 and 1200 miles.
(a) For each plan, find a linear function
C that models the cost in terms of the
number x of miles driven.
(b) Which rental plan is cheaper if the businessman drives 1000 miles? 1200 miles? At
what mileage do the two plans cost the same?
C 1x 2
profit = revenue - cost
P 1x 2
R 1x 2
C 1x 2
S 1x 2
C 1x 2
S 1x 2= U 1x2
U 1x 2
g1x 2g
f 1x 2
Demand: y =-0.6p + 300Demand: y =-0.65p + 28
Supply: y = 8.5p + 45Supply: y = 0.45p + 4
CONTEXTS
218 CHAPTER 2
Linear Functions and Models
32. Buying a Car Kofi wants to buy a new car, and he has narrowed his choices to two
models.
Model A sells for $15,500, gets 25 mi/gal, and costs $350 a year for insurance
Model B sells for $19,100, gets 48 mi/gal, and costs $425 a year for insurance
Kofi drives about 36,000 miles a year, and gas costs about $4.50 a gallon.
(a) Find a linear function A that models the total cost of owning Model A for
x years.
(b) Find a linear function B that models the total cost of owning Model B for
x years.
(c) Find the number of years of ownership for which the cost to Kofi of owning Model
A equals the cost of owning Model B.
33. Commute to Work (See Exercise 59 in Section 2.2.) Jade and her roommate Jari live
in a suburb of San Antonio, Texas, and both work at an elementary school in the city.
Each morning they commute to work traveling west on I-10. One morning Jade leaves
for work at 6:50
A.M., but Jari leaves 10 minutes later. On this trip Jade drives at an
average speed of 65 mi/h, and Jari drives at an average speed of 72 mi/h.
(a) Find a linear equation that models the distance y Jari has traveled x hours after she
leaves home.
(b) Find a linear equation that models the distance y Jade has traveled x hours after Jari
leaves home.
(c) Determine how long it takes Jari to catch up with Jade. How far have they traveled
at the time they meet?
34. Catching Up Kumar leaves his house at 7:30
A.M. and cycles to school. Kumar’s
mother notices that he has left his lunch at home. She leaves the house by car 5 minutes
after Kumar left to give him his lunch. Kumar cycles at an average speed of 8 mi/h, and
his mother drives at an average speed of 24 mi/h.
(a) Find a linear equation that models the distance y Kumar’s mother has traveled x
hours after she left home.
(b) Find a linear equation that models the distance y Kumar has traveled x hours after
his mother has left home.
(d) Determine how long it takes Kumar’s mother to catch up with Kumar. How far have
they traveled at the time they meet?
35. Supply and Demand for Corn An economist models the market for corn by the
following equations:
Here, p is the price per bushel (in dollars), and y is the number of bushels produced and
sold (in billions).
(a) Use the model for supply to determine at what point the price is so low that no corn
is produced.
(b) Use the model for demand to determine at what point the price is so high that no
corn is sold.
(c) Find the equilibrium price and the quantities that are produced and sold at
equilibrium.
36. Supply and Demand for Soybeans An economist models the market for soybeans
by the following equations:
Demand:
y =-0.23p + 5.22
Supply:
y = 0.37p - 1.59
Demand:
y =-1.06p + 19.3
Supply:
y = 4.18p - 11.5
B 1x 2
A 1x 2
CHAPTER 2
Review 219
Here p is the price per bushel (in dollars), and y is the number of bushels produced and
sold (in billions).
(a) Use the model for supply to determine at what point the price is so low that no
soybeans are produced.
(b) Use the model for demand to determine at what point the price is so high that no
soybeans are sold.
(c) Find the equilibrium price and the quantities that are produced and sold at
equilibrium.
37. Median Incomes of Men and Women The gap between the median income of men
and that of women has been slowly shrinking over the past 30 years. Search the Internet
to find the median incomes of men and women for 1965 to 2005.
(a) Find the regression line for the data found on the Internet for the median income
of men.
(b) Find the regression line for the data found on the Internet for the median income
of women.
(c) Use the regression lines found in parts (a) and (b) to predict the year when the
median incomes of men and women will be the same.
38. Population The populations in many large metropolitan districts have recently been
decreasing as residents move to the suburbs. Search the Internet for a city of your
choice where there has been a decrease in the metropolitan population and an increase
in the suburban population.
(a) Find the regression line for the metropolitan population data for the past 40 years.
(b) Find the regression line for the suburban population data for the past 40 years.
(c) Use the regression lines found in parts (a) and (b) to estimate the year in which the
suburban population will equal the metropolitan population.
39. Teacher Salaries The gap between the median salaries for men teachers and women
teachers has recently been shrinking. Search the Internet to find a history for the past
30 years of men and women teachers’ median salaries in your state.
(a) Find the regression line for the data on the men teachers’ median salary.
(b) Find the regression line for the data on the women teachers’ median salary.
(c) Use the regression lines found in parts (a) and (b) to predict the year when the
median teacher’s salary will be equal for men and women.
R
R
R
R
R
R
CHAPTER 2
REVIEW
CONCEPT CHECK
Make sure you understand each of the ideas and concepts that you learned in this chapter,
as detailed below section by section. If you need to review any of these ideas, reread the
appropriate section, paying special attention to the examples.
2.1 Working with Functions: Average Rate of Change
The average rate of change of the function between x a and x b is
average rate of change =
net change in y
change in x
=
f 1b 2- f 1a2
b - a
y = f 1x2
CHAPTER
2
220 CHAPTER 2
Linear Functions and Models
The average rate of change measures how quickly the dependent variable changes
with respect to the independent variable. A familiar example of a rate of change is
the average speed of a moving object such as a car.
2.2 Linear Functions: Constant Rate of Change
A linear function is a function of the form . Such a function is called
linear because its graph is a straight line. The average rate of change of a linear func-
tion between any two values of x is always m, so we refer to m simply as the rate of
change of f. The number b is the starting value of the function (its value when x is 0).
To find the slope of a line graphed in a coordinate plane, we choose two differ-
ent points on the line, and , and calculate
The y-intercept of the graph of any function f is
If is a linear function, then
The graph of f is a line with slope m.
The y-intercept of the graph of f is b.
Thus the rate of change of f is the slope of its graph, and the initial value of f is the
y-intercept of its graph.
2.3 Equations of Lines: Constructing Linear Models
A linear model is a linear function that models a real-life situation. To construct a
linear model from data or from a verbal description of the situation, we use one of
the following equivalent forms of the equation of a line:
Slope-intercept form:
when we know the slope m and the y-intercept b.
Point-slope form:
when we know the slope m and a point that lies on the line.
If we know two points that lie on a line, we first use the points to find the slope
m and then use this slope and one of the given points in the point-slope form to find
the equation of the line.
Horizontal and vertical lines have simple equations:
The vertical line through the point (a, b) has equation x a.
The horizontal line through the point (a, b) has equation y b.
The general form of the equation of a line is
Every line has an equation of this form, and the graph of every equation of this form
is a line.
2.4 Varying the Coefficients: Direct Proportionality
The numbers b and m in the linear equation are called the coefficients
of the equation: b is the constant coefficient and m is the coefficient of x.
If two nonvertical lines have slopes and , then they arem
2
m
1
y = b + mx
Ax + By + C = 0
1x
1
, y
1
2
y - y
1
= m 1x - x
1
2
y = b + mx
f 1x2= b + mx
f 10 2.
slope
rise
run
change in y
change in x
y
2
y
1
x
2
x
1
1x
2
, y
2
21x
1
, y
1
2
f 1x 2= b + mx
CHAPTER 2
Review 221
parallel if they have the same slope: .
perpendicular if they have negative reciprocal slopes: .
The variable y is directly proportional to the variable x (or y varies directly as x)
if there is a constant k such that x and y are related by the equation y kx. The constant
k is called the constant of proportionality. The graph of a proportionality equation is
a straight line with slope k passing through the origin.
2.5 Linear Regression: Fitting Lines to Data
In Section 2.3 we found linear models for data whose scatter plots lie exactly on a
line. Most real-life data are not exactly linear but may appear to lie approximately on
a line. In this case a linear model can still be useful for revealing trends and patterns.
The linear model that we use is called the regression line; it is the “line of best fit”
for the data.
A simple way to find the regression line for a set of data is to use a graphing cal-
culator. (The command for this is LinReg on many calculators.)
A regression line can be found for any set of two-variable data, but this line
isn’t meaningful if too many of the data points lie far away from the line in a scat-
ter plot. The correlation coefficient r is a measure of how closely data fit their re-
gression line (that is, how closely the variables correlate). For any regression line
we have ; values of r close to 1 or indicate a high degree of corre-
lation, and values of r close to 0 indicate little or no correlation.
2.6 Linear Equations: Getting Information from a Model
To construct a model from a verbal description of a real-life situation, we follow
three general steps:
1. Choose the variable in terms of which the model will be expressed. Assign a
symbol (such as x) to the variable.
2. Translate words into algebra by expressing the other quantities in the problem
in terms of the variable x.
3. Set up the model by expressing the fact(s) given about the quantity modeled as
a function of x.
Once we have found a model, we can use it to answer questions about the quantity
being modeled. This will often require solving equations.
2.7 Linear Equations: Where Lines Meet
Some models involve two linear functions that model two different but related quan-
tities. We are often interested in determining when the two functions have the same
value. In this case we need to find the point at which the graphs of the two lines meet.
This can be accomplished in one of two ways:
Graphically, by graphing both lines on the same coordinate plane and esti-
mating the coordinates of the point of intersection
Algebraically, by setting the two functions equal to each other and solving
the resulting equation
The graphical method usually gives just an estimate, but the algebraic method
always gives the exact answer.
- 1- 1 r 1
m
1
= -
1
m
2
m
1
= m
2
x f(x)
0
3
15
27
39
x f(x)
0
6
2 5.5
45
6 4.5
222 CHAPTER 2
Linear Functions and Models
REVIEW EXERCISES
1–6 A function is given (either numerically, graphically, or algebraically). Find the
average rate of change of the function between the indicated points.
1. Between x 4 and x 10 2. Between x 10 and x 30
x F(x)
2
14
412
612
88
10 6
12 3
x G(x)
0
25
10
- 5
20 10
30 30
40 0
50 15
CHAPTER
2
SKILLS
3. Between and x 2 4. Between x 1 and x 3x =-1
5. , between x 1 and x 4
6. , between and t 3
7–8
Determine whether the given function is linear.
7. 8.
9–12
A linear function is given.
(a) Sketch a graph of the function.
(b) What is the slope of the graph?
(c) What is the rate of change of the function?
9. 10. 11. 12.
13–18
A linear function f is described, either verbally, numerically, or graphically.
Express f in the form .
13. The function has rate of change and initial value 10.
14. The graph of the function has slope and initial value 2.
15. 16.
1
3
- 5
f 1x 2= b + mx
g1x 2=-3 + xg1x 2= 3 -
1
2
xf 1x 2= 6 - 2xf 1x 2= 3 + 2x
g1x 2=
x + 5
2
f 1x 2= 12 + 3x2
2
t =-1g1t 2= 6t
2
- t
3
f 1x 2= x
2
+ 2x
f
y
x
0
1
2
g
y
x
0
1
1
CHAPTER 2
Review Exercises 223
17. 18.
27. The line is horizontal and has y-intercept 26.
28. The line is vertical and passes through the point .
29–32
An equation of a line is given.
(a) Find the slope, the y-intercept, and the x-intercept of the line.
(b) Sketch a graph of the line.
(c) Express the equation of the line in slope-intercept form.
29. 30.
31. 32.
33–34
An equation of a line l and the coordinates of a point P are given.
(a) Find an equation in general form of the line parallel to l passing through P.
(b) Find an equation in general form of the line perpendicular to l passing through P.
(c) Graph all three lines on the same coordinate axes.
33. 34.
35–38
Find an equation for the line that satisfies the given conditions.
35. Passes through the origin, parallel to the line
36. Passes through , perpendicular to the y-axis
37. Passes through , perpendicular to the line
38. Passes through , parallel to the line that contains (1, 2) and (3, 8)1- 2, 42
x + 4y + 8 = 013, - 22
14, - 32
2x - 4y = 8
2x + 3y = 6;
P 1- 1, 22y =-2 +
1
2
x;P 12, - 32
5x + 4y + 20 = 03x - 4y - 12 = 0
3 + x = 6 + 2y1 - y =
x
2
1- 3, 262
19–28
Find the equation, in slope-intercept form, of the line described.
19. The line has slope 5 and y-intercept 0.
20. The line has slope and y-intercept 4.
21. The line has slope and passes through the point (1, 3).
22. The line has slope 0.25 and passes through the point .
23. The line passes through the points (2, 4) and (4, 0).
24. The line passes through the points and .
25. 26.
16, 2 21- 3, 02
1- 6, - 32
- 6
-
1
2
2
4
_2
2 4 6 8 10 12
0
y
x
2
4
_2
_4
_6
241_1_2 3
0
y
x
1
1
0
y
x
1
1
0
y
x