General Properties of Flows 307
Ignoring the results of the last example, let us apply the methodology described
above:
1) We first look for the external solution by supposing that the unknown function
has variations of the order of one on the intervals of the same order of magnitude.
To
O(
H
), differential equation [6.73] reduces to:
ttx
1)(
The equation obtained is here an algebraic relation (a zero order differential
equation) which explicitly gives the external solution which is valid nearly
everywhere.
2) The condition that x(t) be zero at the origin is not fulfilled. We must therefore
complete the preceding solution by an internal solution on an interval with a
different scale to the interval where the external solution is valid, otherwise we will
only recover the latter. Let
G
be the order of magnitude of the length scale of the
interval over which the neglected term
x
must be taken into account.
The interval sought of scale
G
must be situated at the origin. In effect, if this was
not the case, we would have
between this interval
o(1)
and the origin a finite interval
on which the results of the external zone would be applicable; the function x would
be equal to 1+
D
t and would not therefore be zero at the origin, which would imply
that nothing had been solved. The only reasonable possibility is therefore to place
our small interval
G
in the neighborhood of the origin.
3) The order of magnitude of
G
can be obtained by supposing that the term
H
x' is
of the same order as that of the variations of x, i.e. of the order of 1:
DG
G
H
|||
11
1)(
ttxtx
We can deduce from this that
H G
, and we need to study the behavior of the
solution in an interval of amplitude
H
close to the origin.
4) We perform the change of variable:
K
H
K
Xtx
t
Neglecting the terms of order
H
, equation [6.73] can be written:
001)(
XXX
KK