538
Chapter
6
Table
6.15.
The three-dimensional electron density distribution in the symmetrically
independent part of the unit cell of CeRhGe3 calculated using the observed structure factors
determined from Le Bail's extraction (Table
6.10)
and phase angles determined by Ce atoms
placed in the 2(a), and 0.25Rh+0.75Ge atoms placed in the 4(d) and
4(c)
[z
=
0.3681 sites of
the space group I4lmrnm
(RF
=
32.2%).
Peak number
x
Y
z Peak height
1 0 0 0 47
2 0 0 0.363 25
3 0.5 0 0.250 23
4 0 0 0.21 1 8
5
0 0 0.100
5
It is possible to use this model of the crystal structure and attempt
Rietveld refinement (as will be illustrated in Chapter
7),
but we will proceed
with testing other space groups from the list of
8
possible (14/mmm, 14rn2,
142m, I4mm, 1422, I4/m,
14
and 14). Analysis of space groups 14m2 and
142m indicates that available low-multiplicity sites are essentially identical
to those of the space group I4/mmm. When these two groups are tested as
described above, the resultant models are also quite suspicious.
The next space group on the list is I4mm (Table
6.16).
This group has no
fixed origin along the Z-axis: one available two fold site 2(a) has coordinates
0,0,z, and the only available 4-fold site has coordinates 1/2,0,z. We note that
there is no reason to recalculate the Patterson function, because its symmetry
remains
I41mmm. To ensure that we do not place any of the atoms
incorrectly we now position only 2 Ce atoms in the 2(a) site in this space
group. Because the origin along the Z-axis can be chosen arbitrarily in this
space group, it does not matter which
z-coordinate is chosen for Ce. After
placing 2 Ce in
2(a) with z
=
0.000, the RF is 42.6
%,
and the resultant
electron density distribution is shown in Table
6.17.
Table
6.16.
Low multiplicity sites available in the space group
I4mm.
Site
Coordinates of symmetrically equivalent points
2(a) o,o,z; 1/2,1/2,1/2+z
4(b) 0,112,z;
-
1/2,o,z; 1/2,0,1/2+z; 0,1/2,1/2+z
8(c)
XJA
-
-
xJ,z;
-
1/2+x, 112+x, 1/2+z; 112-x, 1/2+x, 1/2+z;
x, x,z; x, 42; 112-x, 112-x, 1 12+z; 1 12+x, 1 /2+x,
1
/2+z
8(d) x,o,z;
OAz;
1/2+x, 1/2,1/2+z; 112,1/2+x, 1 /2+z;
x,o,z;
0, x,z;
112-x, 1/2,1/2+z; 112,112-x, 1 /2+z;
There is no sharp reduction of peak heights between any pair of peaks in
Table
6.1 7
except after the first, and therefore, we proceed by adding just
one two fold-site for the next iteration. Choosing peak No.2 and assuming
that it is the next strongest scattering atom, i.e.
Rh,
the distance between this
peak and Ce atom in 2(a) with
z
=
0.000 is normal. The residual did not