284 PARABOLIC EQUATIONS
From our discussion in §5.11.3, we assume that U depends continuously on A
in some interval 0 < A < A. Hence we take A, such that 0 < Al < A2 < A and
let the corresponding steady states U; serve as lower and upper solutions for the
evolution problem with A = Ao, A, < Ao < A2. Then, if the initial condition is
sufficiently close to Uo, so that
U1 < u(x,0) < U2,
then the comparison method ensures that u remains between U, and U2. Hence,
the stability of the steady state Uo follows when we let A, t Ao and A2
.
A0.
*6.6.5 Blow-up
We have frequently seen in this book that nonlinearity can generate singularities in
the solutions of well-posed partial differential equations, be they elliptic, hyperbolic
or parabolic. Such singularity development is a global phenomenon, depending on
data quite remote from the singularity location, and this aspect makes prediction
difficult.
For semilinear equations, some very helpful clues can be found by studying the
monotonicity of the solution in time using the comparison method. Suppose, for
example, that in the Robin problem (6.89) the initial data u(x, 0) = g(x) is a lower
solution, i.e. that it satisfies (6.90) with 8u/8t = 0. Hence u(x, t) > g(x) and we
can show127 that Ou/8t >, 0 for a short time. Thus we can take u(x, h) as a new
subsolution starting from a small enough time t = h. Repeating the process shows
that 8u/8t stays positive and hence, if we can additionally find a smallest steady
state greater than g, then u must tend to this steady state as t -+ oo.
These arguments reveal the following general alternative for semilinear scalar
problems: if g is a lower solution, then, because u is increasing, either u tends to
the smallest equilibrium above g, or u is unbounded. Consider, for example, the
ignition model of §6.6.1 in which
8u =V2u+Ae"
in fl,
u = 0
on 851,
u=0 att=0.
(6.97)
St
We recall from §5.11.3.1 that the steady-state behaviour is characterised by the
existence of a A* such that the continuous minimal branch w of positive solutions
emanating from the origin in the response diagram first turns over at A = A. For
the evolution problem, the initial condition zero is certainly a strict lower solution,
so Ou/8t > 0 for A > 0. Hence, if A < A', then u -> w as t -i oo. In fact, we can
extend the argument above to show that the smallest equilibrium state is stable
both from above and below.
In contrast, if A > A* in (6.97), and indeed if A <, A' and u(x, 0) is too large,
there is the possibility that u is unbounded as t -+ oo. Moreover, it may well
happen that u goes to infinity in finite time, in which case we say that blow-up
has occurred. To demonstrate the inevitability of blow-up when A is sufficiently
127To do this, we need to note that u(x, h) > u(x, 0) for h >, 0. By considering the evolution of
uh(x, t) = u(x, t + h), we can see that uh(x, t) > u(x, t) and hence, taking the limit h j 0, we
find that 8u/8t >, 0.