
CHAPTER 8 The Wess-Zumino Model
169
Terms with Four Spinors
Consider the first term of Eq. (8.33):
−
1
2
∂W
ij
∂φ
k
ζ · χ
k
χ
i
· χ
j
(8.34)
There is no other term of this form. When the three indices are equal, i = j = k,
it is identically zero because it contains the square of spinor components. What
happens when the indices are different? Do we have to set W
ij
equal to a constant?
Actually, this would be too restrictive. To see this, consider identity (A.53). In order
to use this identity, we must keep in mind that the indices i, j, and k are summed
over. Consider, for example, the three terms
∂W
12
∂φ
3
ζ · χ
3
χ
1
· χ
2
+
∂W
31
∂φ
2
ζ · χ
2
χ
3
· χ
1
+
∂W
23
∂φ
1
ζ · χ
1
χ
2
· χ
3
(8.35)
Identity (A.53) tells us that
ζ · χ
3
χ
1
· χ
2
+ ζ · χ
2
χ
3
· χ
1
+ ζ · χ
1
χ
2
· χ
3
= 0 (8.36)
so the three terms of Eq. (8.35) will cancel out at the condition that
∂W
12
∂φ
3
=
∂W
31
∂φ
2
=
∂W
23
∂φ
1
(8.37)
It’s clear that if we assume cyclic symmetry of ∂ W
ij
/∂φ
k
under the permutation of
the three indices i, j, and k, we will have automatic cancellation of Eq. (8.34), all
the terms canceling in groups of three.
As for the second term of Eq. (8.33), there is no identity to save us this time, so
we must impose
∂W
ij
∂φ
†
k
= 0 (8.38)
that is, W
ij
must be a holomorphic function of the φ
k
.
In order for W
ij
χ
i
· χ
j
to be of dimension 4 or less, the most general holomorphic
W
ij
we can write down is
W
ij
= m
ij
+ y
ijk
φ
k
(8.39)