832 27. LIE
GROUPS
ANO
LIE
ALGEBRAS
27.1.4 Integrationon Lie Groups
As any other manifold, one can define integration on Lie groups; i.e., one can
construct nonvanishing n-forms and use Equation (26.46) to define integrals on a
Lie group G. Because
of
the left-invariant property
of
objects on G, it would be
helpfnl if the integration process were also left-invariant.
For
this to happen, the
n-form would have to be left-invariant.
It
turns out that this can be accomplished
more or less urtiquely:
27.1.31.
Proposition.
Let
G be a Lie group
of
dimension n. Then there exists a
left-invariantnonvanishing n-form
1L
thatis uniqueup to a nonzeromultiplicative
constant.
If
G is compact, then
110
is also right-invariant
and
the multiplicative
constant can be chosen to be
I.
Proof
Let
lJoe
be any nonzero n-form on 'Je(G).
The
desired n-form is the left
translation
of
this form, i.e., L;-llJoe' Indeed, let {Xili'=, be left invariant. Then
IJo
g
(X, l
g
, ·
..
, Xnl
g)
= L;_llJoe(X,l
g,
, Xnl
g)
= lJoe(Lg-l*X,l
g
, ,
Lg-l*X
n
Ig)
= lJoe(Xilg-1g,
...
, Xnlg-l
g)
= lJoe(X,le,
...
, Xnl
e).
This shows that
110
is left-invariant. Now note that any other n-form
1Jo~
on 'Je(G)
is a constant multiple
of
lJoe'
Therefore, the corresponding n-form
1Jo~
will be a
constant multiple
of
IJo
g
•
Let x E G and consider
110'
'"
RilJo.
We have
L
* ' L* R* R* L* R*
I
gIL = g 0 xl! = x 0
glt
=
xJL
=
JL
•
where we used the fact that L
g
and R
x
commute and that
110
is left invariant. The
equation above shows that lJo'is also left-invariant. Therefore,
110'
=
CIJo.
If
G is
compact, we can integrate both sides and note that
f
G
110
= f
G
110'
because
110'
is
related to
110
by a change
of
variable. Therefore, c = I and
Ri
110
=
110.
D
The
left-invariant volume element (nonvanishing n-form) guaranteed by the
Haar
measure
proposition above is called Haar
measure.
Since all calculations are done using
some coordinate system, we give an explicit expression
of
the Haar measure in
terms
of
coordinates (parameters)
of
a general Lie group. Let y =
(y',
...
, yr)
be the coordinates
of
the translation
of
x = (x
',
...
,
x")
by g E G. Then we can
write y
=meg, x), so that
dy!
=
(ayi
jaxi)dx
i
=
(ami
jaxi)dx'-
Therefore,
d
'
r
(ami(g,X»)
i r
y
A···
A dy = det .
dx
A···
A
dx
.
ax'
In particnlar,
if
x = 0, the coordinates
of
the identity, theny will be the coordinates
of
g. So, the volume element at g, denoted by
dry,
will be given by
d
r
y = det
(ami
(~'
X»)
I d
r
x.
ax
x=o