Sec.
6.21
Valves
t37
136
Boundary
conditions continued
lch.
6
This
is not
perfectly
accurate
but
it closely
approximates the
accurate
analysis of
the valve.
This
is
given
in the author's book Hydraulic analysis of unsteady
flow
in
pipe
networ,ts. Generally,
analysts do not even correct
the manufacturer's
graph;
so
the results obtained
from an analysis, using this correction, should be significantly
more accurate.
The effect
is not
negligible.
In
a
valve
opening, s increases from
zero
to the
value at
which
the
opening
is to be
steady,
i.e.
unity if the
valve
is to be full open
-
and this
movement must
occur in the
time specified
for
it.
Conversely,
with a valve closure, s runs from unity or whatever
partial
opening exists at the
beginning of the stroke down to zero.It is simple either
to increment
or to decrement the
value
of
s
progressively
but there are many other
different sorts
of
valve which
perform
different functions for which this simple
technique
would not be appropriate.
Examples of such valves are,
for
example,
the
pressure-reducing
valve which operates in such a
way
as to reduce the
pressure
downstream
of itself
to a
preset
value,
the
pressure-sustaining
valve which maintains
the
pressure
upstream
of itself above a
preset
value, valves which close or open
according
to the magnitude
of the
pressure,
the temperature of the flow,
or the flow
itself at some
other
point
in the
network communicated
to the valve's controls
using
some
form of
telemetry.
Far
more complicated types of control
are used
in
various
systems
in
which valves
are used
to control some
particrrlar
variable
such as the depth in
a tank or the
pressure
in a
pressure
vessel. A simple linear response to the difference
between a
control
variable and set
value may be used, but in others the s
value
is controlled
by
the magnitude
of the
time integral of this deficit.
In
all these cases,
the analysis can
be
carried
out
by
specifying
the
way
in which s
varies
with whatever
variable
controls
it,
and then,
by reference
to the array for
K, the
appropriate
value for K can
be
determined.
Once
the
value of K has
been found, the calculation
of
the heads and
velocities on
each side
of
the
valve
must
be undertaken. The
pipe
is first divided into two sections
at the
valve. The upstream
section
willcontain
a
Ax length
immediately
upstream of
the
valve
and
the downstream section
will contain a Ax length downstream of
the
valve. In the upstream
Ax length a
positive
characteristic will be
present
and,
similarly,
in the
downstream section a
negative characteristic will also be
present.
These two
characteristics,
together
with
the equation for the head
loss across the
valve, and the
continuity equation,
will
provide
a
solution of
all unknown
values.
At
point
Nthere
must
be an upstream Nand a downstream N, i.e. Nt and N2, as
there
are
two
values of head and two
values of
velocity
at a
valve
and
at time f * Ar the
apices
of
the two
triangles
must
be designated by Prand Prtorcpresent the two sides
of the
valve at this time
(Fig.
6.4).
The
two characteristic equations
are
,
hr,:
hs
*Or
@o-
u5
* F5)
therefore
h",
hp2:
h^-
hr-?
,",-%r
,r,*
?
,^
*
?
',
-|
n"-
f
r"
but
h",
hP2=#
and
and
uPr.
urr?
where
a,
is
the
cross-sectional
area of
the
upstream
downstream
of
the the
valve- So
*
rl*,
valve
Fig. 6.4.
c-,
*
(h",-
h*) +Dp,
-
DR * Fp
:
o
,
c
-:
- E
(hr,-
hr)
+
Dpz-rrs + lt
:
o
her
h^-%
(u",
-
u^
*
F^)
pipe
ry:v-(?.or',)',,
and
a2
is that
of
the
PiPe