50 The Allievi interlocking
equations and
graphical
methods
[Ch.
2
reservoir at the upstream
end and all the
parameters
of the
pipeline
must be constant
throughout its length. To illustrate
how the
interlocking
equations
can
be used, the
downstream boundary
condition will be assumed to be a
valve.
This is the case that
Allievi
used to demonstrate the technique but it is emphasized that
the method
is not
confined to downstream valves.
Also it should
be
realized that it can be adapted to
deal with more complex
circumstance
than
the simple
pipeline.
It
seems
improbable
that
any modern analyst would want to employ these more
complex approaches,
even though
they are
possible.
Modern approaches are far more
capable
than is the
Allievi
rnethod,
but
the Allievi approach is ingenious and
enables
the
student
to
understand
the fundamentals of
pressure
transients. For a detailed
exposition
of
these
techniques
see G. Rich's
Hydraulictransients and
C. Jaeger's Engineeringfluid
mechanics.
To illustrate how the above equations
can be
used, the case
of a slowly
moving
(opening
or closing) downstream valve
will
be described. For
a
valve, use a
quasi-
steady
description of the
flow through it, based
on Bernoulli's equation
qn,:
A"1/2gh" where A" is
the effective
area
of
the
valve
and is equal to
CuA,.
A" is the
area
available
for flow through the
valve
and C6 is the coefficient
of discharge for
this
area. q"
is the flow
through the
valve
and
h,is the
head
just
upstream of the
valve.
Strictly ft, should be the total head, i.e. the
pressure
head
plw plus
the kinetic energy
head
u2l2g but
in most
pipelines
the
velocity
head term
is so small in
comparison
with
the pressure
head that it is
permissible
to ignore it.
Therefore
A
Di=?
l/Lsh,
where
1o is the
pipe
cross-sectional area,
and hris
the
value
of
hu
at instant
i
but
A
uo:
?
t/2gho.
tap
So
t); A"
lh,
A--E"Vr'"
Denote
A"!A"n
by
n
ana
lkth
by
(
which
are the same symbols as those
employed
by Allievi. Then
!
:
rl{,.
Us
Substituting these
symbols
in
the interlocking equations,
Sec. 2.11
Analytic methods
h,
*h,-,
-)
-.cuo
(u,-r-
9\
ho' ho
-
Slro
\
uo uo/
51
e?
+C?-r- Z=Zp(q'-rC-r
-
t,{,)
where
p:
cudlghs.
These
are the interlocking equations
of Allievi for the case
of
a closing-opening
valve.
Using the techniques demonstrated above,
different
boundary conditions
can
be substituted
both upstream and downstream
and
solutions obtained.
Even
networks
can
be solved
by this method.
Reflectance
and transmittance
coefficients
can
be derived
for such
boundary
conditions as
junctions
and for even more
complicated
circumstances. Even so these devices
solve
problems
which are not
very
closely related
to reality because of the limiting nature
of the
assumptions
that had to
be
made
initially to
reduce
the original equations to
a state in
which the
Von
Riemann
[2]
solution
could be obtained. For
this reason it is suggested that
this
technique
of solution should
not be
considered as accurate. Also,
as
friction is
omitted from the analysis, such methods could not
produce
accurate results
anyway
unless
the
system
is of a high
pressure
type in which
low
velocities
are
present.
The
supply
pipework
of
a Pelton
wheel
hydropower plant
is of such
a type but
most
systems
are not; another
technique
of analysis is required. Even
so,
the
Allievi
interlocking
equations
demonstrate a
great
deal about the nature of waterhammer
and how waves
travel up and down
pipes,
reflecting differently at different boundary
conditions.
For
simple
pipelines,
slow
valve
closures can be
very
easily
solved
without
recourse
to
graphical
or
computing methods.
On the occasions for
which this
is sufficiently
accurate
it could
be a
method
of choice.
2.3.2
Solution of the
Allievi
[3]
interlocking
equations
The solution
of the
Allievi interlocking
equations is a matter of the
utmost
simplicity.
Initially when
the
valve
is fully
open
(say)
the
value
of
rlo:1
and
(o:L;
so
e?
-
t:Zp(l
-
q(r)
where
p
-
cudLghs and
q1
must be known
and specified.
So
a
quadratic
in
(,
results. Having
solved
(.,
the next
stage
of the analysis can be
undertaken.
q2
is known
and
so
the following
equation is obtained:
CZ
+
e?
-
2
-
Zp(rtrh
-
\ze).
Again,
this is a
quadratic
in
(,
with
all other constants known.
So
6,
can be found
and
the process
can then
be repeated for as many multiples
of
las may be required.
Then
and
Ur
:
Uolr(
r,
U2:
Uo\zez,
Us: Dons(3,
etC.