2.2. The Cauchy Problem in - oo < t < oo. The Adjoint Equation
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(see Section 6 and references there.) In particular, if a(A) is contained in the
imaginary axis, then A E (2 (1, 0). (Recall that if the spectrum of a normal
operator is contained in the imaginary axis, then A= iB, where B is
self-adjoint.) The propagator S(t) can be computed by formula (2.2.20) and
we have
IIS(t)II=ew't,
IIS(-t)II =e"2t (t, 0).
Let A be an operator in C3+(C, w). It is of great interest to know
whether the adjoint A* belongs to E+ as well. The question has a very simple
answer when E is reflexive; in fact, in this case D(A*) is dense in E*,
p(A*) = p(A), and R(X; A*) = R(X; A)* (Section 4). It follows then that A*
satisfies as well (and with the same constants) inequalities (2.1.11) and thus
belongs to (2+ The same is true, of course, in relation to the class e. To
identify S*(-), the propagator of
u'(t) = A*u(t),
we observe that if u E E and u* E E*,
(2.2.22)
fooo e-'"(S*(t)u*, u) dt = (R(µ; A*)u*, u) = (u*, R(µ; A)u)
0
= f 00 e-"t(S(t)*u*, u) dt (µ > w).
It follows then from uniqueness of Laplace transforms that S*(t) = S(t)*
for t > 0. If A belongs to (2, a similar argument takes care of S*(t) for t
negative. We formalize these comments in the following
2.2.9 Theorem. Let A E (+(C, w), and assume E reflexive. Then
A* E e+(C, w) as well. The solution operator of (2.2.22) is where
is
the solution operator of 2.2.8. The same conclusion holds for the class (2 (C, W).
If the space E is not reflexive, the situation is considerably more
complicated. In fact, it may be no longer true that A* is densely defined;
worse yet, there might be elements u* of D(A*) for which no solution of
(2.2.22) with u* as initial datum exists.
2.2.10 Example. We use the result in Example 2.2.5 with p =1. In this case
E* = L°°(- oo, oo). To compute the adjoint of A, we observe that if u E D(A*), then
there exists v( = A*u) in E* such that
f u(x)w'(x) dx = f v(x)w(x) dx
(2.2.23)
for all w E D(A). Since this equality must hold in particular when w is a test
function, it follows that u' = - v (in the sense of distributions), so that u, if
necessary modified in a null set, is absolutely continuous. Conversely, if u is